[Tex/LaTex] TikZ picture: two arrow; one over the other

tikz-pgf

I have the following code:

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{matrix,arrows}

\begin{document}
  \[
        \begin{tikzpicture}
         \matrix (m) [matrix of math nodes,row sep=3em,column sep=1em,minimum width=2em]{
              A &   & G \\
                & S &   \\
         };
         \path[-stealth]
            (m-1-1) edge node [above] {$f$} (m-1-3)
            (m-1-1)  edge [bend right] node [left] {$p\;$} (m-2-2)
            (m-1-3) edge node [right] {$\;q$} (m-2-2)
            (m-2-2) edge node [right] {$\epsilon$} (m-1-1);
         \path[-stealth]
            ([yshift=5pt]m-1-1) edge node [right] {$g$} ([yshift=5pt]m-1-3);
        \end{tikzpicture}
    \]
\end{document}

I dare you to compile it. Then you will get a disgusting output. What I want is to get the two arrow on top one over the other (just like corolary 1.3.1.5, page 70, in the notes on http://math.umn.edu/~kwlan/articles/cpt-PEL-type-thesis-revision.pdf).

Can anyone help? I would love if the solution didn't modify too much the way I coded the diagram since it is the way I always do it (with the matrix) but beggers can't be choosers, so.

Best Answer

Here is an attempt to fix it by using the .east and .west anchors:

enter image description here

Notes:

Not sure why you were using math mode -- I have removed that in the below MWE.

Code:

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{matrix,arrows}

\begin{document}
        \begin{tikzpicture}
         \matrix (m) [matrix of math nodes,row sep=3em,column sep=1em,minimum width=2em]{
              A &   & G \\
                & S &   \\
         };
         \path[-stealth]
            (m-1-1.east) edge node [above,yshift=1.0ex] {$f$} (m-1-3.west)
            (m-1-1) edge [bend right] node [left] {$p\;$} (m-2-2)
            (m-1-3) edge node [right] {$\;q$} (m-2-2)
            (m-2-2) edge node [right] {$\epsilon$} (m-1-1);
         \path[-stealth]
            ([yshift=5pt]m-1-1.east) edge node [below,,yshift=-1.0ex] {$g$} ([yshift=5pt]m-1-3.west);
        \end{tikzpicture}
\end{document}

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

The source of the difficulty is that ellipses are constructed in a particular way in TikZ. They are paths that start from the x-axis and proceed counter-clockwise around their centre. The vast majority of the time, the exact parametrisation doesn't matter. You appear to have found the one situation where it does!

In the actual question, you only want to be able to mirror the ellipse, and so draw it starting from the negative x-axis (the title of the question suggests a more flexible approach). That's actually not too hard since we can exploit the symmetry of the ellipse. The key is to provide it with a negative x-radius, since then it will start from the negative x-axis (and proceed clockwise, but we could correct for that by negating the y-radius as well). To do this, we interrupt the call from the node shape to the drawing command and flip the sign of the x-radius. The simplest way to do this is to redefine the \pgfpathellipse macro to do the negation and then call the original macro. The following code does this.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations,shapes,decorations.markings}
\makeatletter
\let\origpgfpathellipse=\pgfpathellipse
\def\revpgfpathellipse#1#2#3{%
  #2%
  \pgf@xa=-\pgf@x
  \origpgfpathellipse{#1}{\pgfqpoint{\pgf@xa}{0pt}}{#3}}
\makeatother

\tikzset{
  reversed ellipse/.style={
    ellipse,
    reverse the ellipse%
  },
  reverse the ellipse/.code={
    \let\pgfpathellipse=\revpgfpathellipse
  }
}
\begin{document}
\begin{tikzpicture}
\node[ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,0) {hello world};

\node[reversed ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,-2) {hello world};
\end{tikzpicture}

\end{document}

Here's the result:

rotated ellipse

(the arrow got clipped, but you can see where it lies)

[Tex/LaTex] How to define the default vertical distance between nodes

I don't really get the question so I hope this is what you wanted. If you include a full document (such that we copy paste and see the problem on our systems) things are much more easier.

Here, you can change the default setting within a scope but your block style had a node distance which was resetting every time it is issued. I've made it 2mm such that we can see the difference easier.

\documentclass[tikz]{standalone}
\usetikzlibrary{arrows,shapes.geometric,positioning}

\begin{document}
\begin{tikzpicture}[decision/.style={diamond, draw, text width=4.5em, text badly centered, node distance=3.5cm, inner sep=0pt},
                    block/.style   ={rectangle, draw, text width=6em, text centered, rounded corners, minimum height=4em, minimum height=2em},
                    cloud/.style   ={draw, ellipse, minimum height=2em},
                    line/.style    ={draw,-latex'},
                    node distance = 1cm, 
                    auto]
    \node [block] (1st) {1st};
    \node [block, right= of 1st]  (2nd1) {2nd1};
\begin{scope}[node distance=2mm and 10mm]%Here we change it for everything inside this scope
    \node [block, above= of 2nd1] (2nd2) {2nd2};
    \node [block, below= of 2nd1] (2nd3) {2nd3};
    \node [block, right= of 2nd1] (3rd1) {3rd1};
    \node [block, above= of 3rd1] (3rd2) {3rd2};
    \node [block, above= of 3rd2] (3rd3) {3rd3};
\end{scope}
    \node [block, below= of 3rd1] (3rd4) {3rd4};
    \node [block, below= of 3rd4] (3rd5) {3rd5};

    \path [line] (1st) -- (2nd1);
    \path [line] (2nd1) -- (2nd2);
    \path [line] (2nd1) -- (2nd3);
    \path [line] (2nd2) -- (3rd3);
    \path [line] (2nd1) -- (3rd1);
    \path [line] (1st) -- (2nd1);
\end{tikzpicture}
\end{document}