[Tex/LaTex] How to draw loop arrow and right left arrow

tikz-arrowstikz-pgf

I attempt to draw my map and I'm stuck in drawing the following \

drawing a loop above from 1 to 1
drawing loop down from -1 to -1
drawing bend above arrow from 2 and ending in 3 and bend down arrow from 3 and ending in 2
drawing bend above arrow from -2 and ending in -3 and bend down arrow from -3 and ending in -2
I also drew an "arrow" from 3 to -4 and another one from 4 to -3 but how to make them appear as a double-headed arrow connecting them. Sorry, I'm still a leTEX learner and I attempted a lot with no luck! This is my attempt and could you please help me and look at my handed drwawing picture as well.

\documentclass[12pt]{article}
\usepackage{amsmath}
\usepackage[english]{babel}
\usepackage{pgf,tikz} % for a sample picture that is included below
\usetikzlibrary{arrows}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{document}
\definecolor{uuuuuu}{rgb}{0.26666666666666666,0.26666666666666666,0.26666666666666666}

\tikzset{graph-1/.style = {
  line cap = round,
 line join = round,
         > = triangle 45,
 x=0.37cm, y=0.37cm,
 every node/.append style = {inner ysep=2mm}
                            }
        }% end of tikzset

    \begin{figure}[ht]
    \centering
    \begin{tikzpicture}[graph-1]

\foreach \x in {0, 2, 4}
\foreach \x/\label in {0/\scriptstyle1, 2/\scriptstyle2, 4/\scriptstyle3, 6/\scriptstyle4, 8/\scriptstyle5}
\draw[fill=uuuuuu]  (\x,1.5) circle (1.3pt) node[above] {$\label$};
%
\foreach \x/\label in {0/\scriptstyle-1, 2/\scriptstyle -2, 4/\scriptstyle-3, 6/\scriptstyle-4, 8/\scriptstyle-5}
\draw[fill=uuuuuu]  (\x,-1.5) circle (1.3pt) node[below] {$\label$};
\foreach \x in {4}
\draw  (\x,1.5) -- (\x+2,-1.5);
\foreach \x in {6}
\draw  (\x,1.5) -- (\x-2,-1.5);
%
%\foreach \x in {0}  [it does not work to draw a loop]
%\draw [uuuuuu,->,gray, loop above] (\x) edge (\x)
%\draw [uuuuuu] (\x) --  (\x)
%\draw (\x) -- (\x)
%
\node[left] at (-.3,0) {$\pi=$};
\end{tikzpicture}
 \end{figure} 
\end{document}

Best Answer

Possible solution:

You should use the proper TikZ commands if you want to create nodes with labels, that is: nodes with labels. Then you can easily draw arrows from one node to the other. Also, it does not make that much sense to use a foreach loop only for one single command.

I amended your code. The two foreach loops create the nodes and give them the names t0, t2, t4, t6, t8 and b0, b2 etc.

You may want to draw the arrows differently.

\documentclass[12pt]{article}
\usepackage{pgf,tikz} 
\usetikzlibrary{backgrounds}
\usetikzlibrary{arrows}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{document}
\definecolor{uuuuuu}{rgb}{0.26666666666666666,0.26666666666666666,0.26666666666666666}

\tikzset{graph-1/.style = {
  > = triangle 45,
  x=0.37cm, y=0.37cm }
}% end of tikzset

\begin{figure}[ht]
  \centering
  \begin{tikzpicture}[graph-1]

    \foreach \x/\label in {0/\scriptstyle1, 2/\scriptstyle2, 4/\scriptstyle3, 6/\scriptstyle4, 8/\scriptstyle5}
      \node[fill=uuuuuu,inner sep=1.3pt,circle,label=above:{$\label$}] at (\x,1.5) (t\x) {};

    \foreach \x/\label in {0/\scriptstyle-1, 2/\scriptstyle -2, 4/\scriptstyle-3, 6/\scriptstyle-4, 8/\scriptstyle-5}
      \node[fill=uuuuuu,inner sep=1.3pt,circle,label=below:{$\label$}] at (\x,-1.5) (b\x) {};

    \draw[<->] (t6) -- (b8);
    \draw[<->] (t8) -- (b6);

    \draw[uuuuuu,->] (t0) to[loop below] (t0);
    \draw[uuuuuu,->] (b0) to[loop above] (b0);

    \draw[uuuuuu,->] (t2) to[bend right] (t4);
    \draw[uuuuuu,->] (t4) to[bend right] (t2);
    \draw[uuuuuu,->] (b2) to[bend left] (b4);
    \draw[uuuuuu,->] (b4) to[bend left] (b2);

    \node[left] at (-.3,0) {$\pi=$};
  \end{tikzpicture}
  \hfil

\end{figure} 

\end{document}

Edit: With smaller arrow heads and the loops to the other side.

\documentclass[12pt]{article}
\usepackage{pgf,tikz} 
\usetikzlibrary{backgrounds}
\usetikzlibrary{arrows}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{document}
\definecolor{uuuuuu}{rgb}{0.26666666666666666,0.26666666666666666,0.26666666666666666}

\tikzset{graph-1/.style = {
  >=stealth,
  x=0.37cm, y=0.37cm }
}% end of tikzset

\begin{figure}[ht]
  \centering
  \begin{tikzpicture}[graph-1]

    \foreach \x/\label in {0/\scriptstyle1, 2/\scriptstyle2, 4/\scriptstyle3, 6/\scriptstyle4, 8/\scriptstyle5}
      \node[fill=uuuuuu,inner sep=1.3pt,circle,label=above:{$\label$}] at (\x,1.5) (t\x) {};

    \foreach \x/\label in {0/\scriptstyle-1, 2/\scriptstyle -2, 4/\scriptstyle-3, 6/\scriptstyle-4, 8/\scriptstyle-5}
      \node[fill=uuuuuu,inner sep=1.3pt,circle,label=below:{$\label$}] at (\x,-1.5) (b\x) {};

    \draw[<->] (t6) -- (b8);
    \draw[<->] (t8) -- (b6);

    \draw[uuuuuu,->] (t0) to[out=135,in=45,looseness=30] (t0);
    \draw[uuuuuu,->] (b0) to[out=-135,in=-45,looseness=30] (b0);

    \draw[uuuuuu,->] (t4) to[bend left] (t2);
    \draw[uuuuuu,->] (t2) to[bend left] (t4);
    \draw[uuuuuu,->] (b2) to[bend left] (b4);
    \draw[uuuuuu,->] (b4) to[bend left] (b2);

    \node[left] at (-.3,0) {$\pi=$};
  \end{tikzpicture}
  \hfil

\end{figure} 

\end{document}

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

The source of the difficulty is that ellipses are constructed in a particular way in TikZ. They are paths that start from the x-axis and proceed counter-clockwise around their centre. The vast majority of the time, the exact parametrisation doesn't matter. You appear to have found the one situation where it does!

In the actual question, you only want to be able to mirror the ellipse, and so draw it starting from the negative x-axis (the title of the question suggests a more flexible approach). That's actually not too hard since we can exploit the symmetry of the ellipse. The key is to provide it with a negative x-radius, since then it will start from the negative x-axis (and proceed clockwise, but we could correct for that by negating the y-radius as well). To do this, we interrupt the call from the node shape to the drawing command and flip the sign of the x-radius. The simplest way to do this is to redefine the \pgfpathellipse macro to do the negation and then call the original macro. The following code does this.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations,shapes,decorations.markings}
\makeatletter
\let\origpgfpathellipse=\pgfpathellipse
\def\revpgfpathellipse#1#2#3{%
  #2%
  \pgf@xa=-\pgf@x
  \origpgfpathellipse{#1}{\pgfqpoint{\pgf@xa}{0pt}}{#3}}
\makeatother

\tikzset{
  reversed ellipse/.style={
    ellipse,
    reverse the ellipse%
  },
  reverse the ellipse/.code={
    \let\pgfpathellipse=\revpgfpathellipse
  }
}
\begin{document}
\begin{tikzpicture}
\node[ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,0) {hello world};

\node[reversed ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,-2) {hello world};
\end{tikzpicture}

\end{document}

Here's the result:

rotated ellipse

(the arrow got clipped, but you can see where it lies)

[Tex/LaTex] Numerical conditional within tikz keys

I am definitely unfamiliar with both beamer and tikz (do not quite get what the \only are supposed to do) but perhaps this could go in the direction you want:

\documentclass{beamer}
\usepackage{tikz}
\usetikzlibrary{chains}
\newcounter{count}

% helper macro:
\long\def\GobToSemiColon #1;{}

\newcommand\myPicture{
\begin{tikzpicture}
  \begin{scope}[start chain = going below]
  \ifnum\value{count}<1 \expandafter\GobToSemiColon\fi
  \ifnum\value{count}>3 \expandafter\GobToSemiColon\fi
  \node[draw, rectangle, on chain] {display only when counter is between
    1 and 3};

  \ifnum\value{count}>-1 \expandafter\GobToSemiColon\fi
  \node[draw, rectangle, on chain] {display only when counter is
    negative}; 

  \ifnum\value{count}<100 \expandafter\GobToSemiColon\fi
  \ifnum\value{count}>200 \expandafter\GobToSemiColon\fi  
  \node[draw, rectangle, on chain] {display only if counter is between
    100 and 200};

  \ifnum\value{count}<3 \expandafter\GobToSemiColon\fi
  \ifnum\value{count}>20 \expandafter\GobToSemiColon\fi
  \node[draw, circle, on chain] {only when counter is in the range 3 to 20};
  \end{scope}
\end{tikzpicture}
}

\begin{document}
\begin{frame}
\only{\setcounter{count}{-3}\myPicture}
\only{\setcounter{count}{105}\myPicture}
\only{\setcounter{count}{39}\myPicture}
\only{\setcounter{count}{2}\myPicture}
\only{\setcounter{count}{5}\myPicture}
\end{frame}
\end{document}

beamer

Best Answer

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

[Tex/LaTex] Numerical conditional within tikz keys

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