TikZ figure using nodes and arrows

arrowsnodestikz-pgf

I am planning to draw the following figures.

The arrows are drawn by hand, they should be rounded.

All I come up with the following MWE.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{calc}

\usetikzlibrary{fit,positioning,hobby}
\usetikzlibrary{decorations.text}
\usetikzlibrary{decorations.pathreplacing}

\begin{document}

    \begin{tikzpicture}
    \node (one) at (0,0)   {$68 \times 62$}; 
    \node (two) at (5,0)  {$6 \times 7$};
    \node (three) at (7,0)  {$8 \times 2$};
    \draw [->,thick,postaction={decorate,decoration={raise=1ex,text along path,text align=center,text={|\footnotesize|{distance}{}}}}] (one) to [out=45,in=135] (two);
    \draw [->,thick,postaction={decorate,decoration={raise=-1.5ex,text along path,text align=center,text={|\footnotesize|{text}{}}}}] (one) to [bend right=45] (three);
    \end{tikzpicture}  
    
\end{document}

I got stuck drawing arrow over arrow shown in the figure. How can I draw the figure. Can you suggest something?

Best Answer

You can use the width=() function of the calc library and inner xsep=0pt to quite exactly position the arrows over or below the digits inside the left node. This is working because all the digits have the same width which is more or less 1ex.

(More correct would, of course, be for example [xshift={width("$68 \times 6$")-width("$6$")/2}.one north west], which means: shift to the right as far as $68 \times 6$ is wide minus half of the width of $6$ starting from the upper left corner of the node one.)

I simplified you code a bit and came up with this:

\documentclass[border=1mm, tikz]{standalone}

\usetikzlibrary{calc, shapes.misc}

\begin{document}

    \begin{tikzpicture}[digits/.style={inner xsep=0pt, inner ysep=2pt}]
    
    \node[digits] (one) at (0,0) {$68 \times 62$}; 
    \node[rounded rectangle, rounded rectangle right arc=none, draw] (two) at (3,0) {$6 \times 7$};
    \node[rounded rectangle, rounded rectangle left arc=none, draw] (three) at (4.25,0) {$8 \times 2$};

    \draw[thick] ([xshift={width("$6$")-1ex/2}]one.north west) to [bend left=45] node[above] (label above) {digits equal} ([xshift={width("$68 \times 6$")-1ex/2}]one.north west);

    \draw[thick] ([xshift={width("$68$")-1ex/2}]one.south west) to [bend right=45] node[below] (label below) {sum of digits $= 10$} ([xshift={width("$68 \times 62$")-1ex/2}]one.south west);

    \draw[->, thick, shorten >=2pt] (label above) to [bend left=45] node[above] {multiply} (two);
    
    \draw[->, thick, shorten >=2pt] (label below) to [bend right=45] node[below] {multiply} (three);
    
    \end{tikzpicture}
    
\end{document}

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

The source of the difficulty is that ellipses are constructed in a particular way in TikZ. They are paths that start from the x-axis and proceed counter-clockwise around their centre. The vast majority of the time, the exact parametrisation doesn't matter. You appear to have found the one situation where it does!

In the actual question, you only want to be able to mirror the ellipse, and so draw it starting from the negative x-axis (the title of the question suggests a more flexible approach). That's actually not too hard since we can exploit the symmetry of the ellipse. The key is to provide it with a negative x-radius, since then it will start from the negative x-axis (and proceed clockwise, but we could correct for that by negating the y-radius as well). To do this, we interrupt the call from the node shape to the drawing command and flip the sign of the x-radius. The simplest way to do this is to redefine the \pgfpathellipse macro to do the negation and then call the original macro. The following code does this.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations,shapes,decorations.markings}
\makeatletter
\let\origpgfpathellipse=\pgfpathellipse
\def\revpgfpathellipse#1#2#3{%
  #2%
  \pgf@xa=-\pgf@x
  \origpgfpathellipse{#1}{\pgfqpoint{\pgf@xa}{0pt}}{#3}}
\makeatother

\tikzset{
  reversed ellipse/.style={
    ellipse,
    reverse the ellipse%
  },
  reverse the ellipse/.code={
    \let\pgfpathellipse=\revpgfpathellipse
  }
}
\begin{document}
\begin{tikzpicture}
\node[ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,0) {hello world};

\node[reversed ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,-2) {hello world};
\end{tikzpicture}

\end{document}

Here's the result:

rotated ellipse

(the arrow got clipped, but you can see where it lies)

[Tex/LaTex] How to define the default vertical distance between nodes

I don't really get the question so I hope this is what you wanted. If you include a full document (such that we copy paste and see the problem on our systems) things are much more easier.

Here, you can change the default setting within a scope but your block style had a node distance which was resetting every time it is issued. I've made it 2mm such that we can see the difference easier.

\documentclass[tikz]{standalone}
\usetikzlibrary{arrows,shapes.geometric,positioning}

\begin{document}
\begin{tikzpicture}[decision/.style={diamond, draw, text width=4.5em, text badly centered, node distance=3.5cm, inner sep=0pt},
                    block/.style   ={rectangle, draw, text width=6em, text centered, rounded corners, minimum height=4em, minimum height=2em},
                    cloud/.style   ={draw, ellipse, minimum height=2em},
                    line/.style    ={draw,-latex'},
                    node distance = 1cm, 
                    auto]
    \node [block] (1st) {1st};
    \node [block, right= of 1st]  (2nd1) {2nd1};
\begin{scope}[node distance=2mm and 10mm]%Here we change it for everything inside this scope
    \node [block, above= of 2nd1] (2nd2) {2nd2};
    \node [block, below= of 2nd1] (2nd3) {2nd3};
    \node [block, right= of 2nd1] (3rd1) {3rd1};
    \node [block, above= of 3rd1] (3rd2) {3rd2};
    \node [block, above= of 3rd2] (3rd3) {3rd3};
\end{scope}
    \node [block, below= of 3rd1] (3rd4) {3rd4};
    \node [block, below= of 3rd4] (3rd5) {3rd5};

    \path [line] (1st) -- (2nd1);
    \path [line] (2nd1) -- (2nd2);
    \path [line] (2nd1) -- (2nd3);
    \path [line] (2nd2) -- (3rd3);
    \path [line] (2nd1) -- (3rd1);
    \path [line] (1st) -- (2nd1);
\end{tikzpicture}
\end{document}

enter image description here

Best Answer

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

[Tex/LaTex] How to define the default vertical distance between nodes

Related Question