I'd like the \vdots
in this chain to have the same distance to both of the arrows. I know that I could manually shift the node so that it looks right, but there must be a better solution. How?
\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{chains}
\begin{document}
\begin{tikzpicture}[start chain=going below,every join/.style={->}]
\node [on chain, join] {A};
\node [on chain, join] {$\vdots$};
\node [on chain, join] {B};
\end{tikzpicture}
\end{document}
Best Answer
\vdots
has been designed for matrices. You can use a modified version that doesn't add space at its top: