[Tex/LaTex] Create a good looking 2-actor normal-form game such as Prisoner’s Dilemma

heightmatricestikz-pgf

I am having difficulties in adjusting the TikZ code to get a symmetrical output matrix; I guess the * is the reason the right block is somehow higher?

\documentclass[a4paper,fontsize=12pt,a4paper,DIV=10,BCOR=10mm,twoside,titlepage=false,openany,pagesize]{scrbook}

\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage{blindtext}
\setkomafont{disposition}{\normalfont\bfseries}

\usepackage{tikz}
\usetikzlibrary{calc,matrix,positioning}
\begin{document}

\begin{figure}[h]
\centering
\caption{Collective action problem in the Prisoners' Dilemma}
\label{Collective action problem in the Prisoners' Dilemma}
\begin{tikzpicture}[element/.style={ minimum width=1.75cm,minimum height=0.85cm}]
\matrix (m) [matrix of nodes,nodes={element},column sep=-\pgflinewidth, row sep=-\pgflinewidth,]{
         & Cooperate & Defect  \\
Cooperate & |[draw]|3,3 & |[draw]|1,4 \\
Defect & |[draw]|4,1 & |[draw]|2,2* \\
};
\node[above=0.25cm] at ($(m-1-2)!0.5!(m-1-3)$){\textbf{Actor A}};
\node[rotate=90] at ($(m-2-1)!0.5!(m-3-1)+(-1.25,0)$){\textbf{Actor B}};
 \node [below=1.5cm, align=flush center,text width=8cm]
        {\begin{scriptsize}
            Number left (right) of comma refers to A's (B's) preference ordering (1 = worst outcome; 4 = best outcome). * indicates the equilibrium.         
        \end{scriptsize}
        };
\end{tikzpicture}
\end{figure}
\end{document}

Best Answer

You can "pretend" that the * is not here (i.e: it takes no space) by putting \smash{\rlap{*}} instead of simply *. This way not only all cells will have the same size, but also the 2.2 will be vertically aligned with 1.4:

Result

Related Solutions

[Tex/LaTex] How to create a matrix normal form

If you need the vertical and horizontal lines around the matrix blocks, the following solution (which also doesn't require TikZ) may be of interest. (I've updated the example to reflect the update in your question, which appears to require an extra \ddots row/column.)

Note that I use the array environment rather than the matrix (or pmatrix) environment as it's necessary to right-align the contents of some columns.

\documentclass{article}
\usepackage{amsmath,array}
\renewcommand\arraycolsep{4pt} % default value: 6pt
% short-hand commands for multicolumn entries with vertical bar
% on left and right hand sides, respectively
\newcommand{\mcl}[1]{\multicolumn{1}{|r}{#1}}
\newcommand{\mcr}[1]{\multicolumn{1}{r|}{#1}}
\begin{document}
\begin{equation*}
\left( \,\begin{array}{rcr rcr rr c rr}
\cline{1-3}
 \mcl{1} &        & \mcr{}  \\
 \mcl{}  & \ddots & \mcr{}  \\
 \mcl{}  &        & \mcr{1} \\
\cline{1-6}
 & & & \mcl{-1} &        & \mcr{}  \\
 & & & \mcl{}   & \ddots & \mcr{}  \\
 & & & \mcl{}   &        & \mcr{-1}\\
\cline{4-8}
 & & & & & & \mcl{\cos \omega} & \mcr{-\sin \omega}\\
 & & & & & & \mcl{\sin \omega} & \mcr{ \cos \omega}\\
\cline{7-8} 
 & & & & & & & & \ddots\\
\cline{10-11}
 & & & & & & & & & \mcl{\cos \omega} & \mcr{-\sin \omega}\\
 & & & & & & & & & \mcl{\sin \omega} & \mcr{ \cos \omega}\\
\cline{10-11}
\end{array}\,\right)
\end{equation*}
\end{document}

enter image description here

Addendum: Using the \boxed macro, the code that sets up this matrix can be simplified considerably:

\documentclass{article}
\usepackage{amsmath,array}
\renewcommand\arraycolsep{4pt} % default value: 6pt
\begin{document}
\begin{equation*}
\left( \,
\begin{array}{r@{}r@{}r r r}  % @{} is used twice to suppress intercolumn whitespace
  \boxed{ \begin{array}{rrr}              % First block
    1 \\
    & \ddots\\
    & & 1 \\
  \end{array} } \\
  & \boxed{ \begin{array}{rrr}            % Second block
      -1 \\
      & \ddots\\
      & & -1\\
   \end{array} } \\
  & & \boxed{ \begin{array}{rr}           % Third block
        \cos \omega & -\sin \omega\\
        \sin \omega &  \cos \omega\\
      \end{array} } \\
  & & & \ddots\\                          % Fourth "block" -- not boxed
  & & & & \boxed{ \begin{array}{rr}       % Fifth block
            \cos \omega & -\sin \omega\\
            \sin \omega &  \cos \omega\\
          \end{array} } \\
\end{array}\,\right)
\end{equation*}
\end{document}

enter image description here

[Tex/LaTex] How to define the default vertical distance between nodes

I don't really get the question so I hope this is what you wanted. If you include a full document (such that we copy paste and see the problem on our systems) things are much more easier.

Here, you can change the default setting within a scope but your block style had a node distance which was resetting every time it is issued. I've made it 2mm such that we can see the difference easier.

\documentclass[tikz]{standalone}
\usetikzlibrary{arrows,shapes.geometric,positioning}

\begin{document}
\begin{tikzpicture}[decision/.style={diamond, draw, text width=4.5em, text badly centered, node distance=3.5cm, inner sep=0pt},
                    block/.style   ={rectangle, draw, text width=6em, text centered, rounded corners, minimum height=4em, minimum height=2em},
                    cloud/.style   ={draw, ellipse, minimum height=2em},
                    line/.style    ={draw,-latex'},
                    node distance = 1cm, 
                    auto]
    \node [block] (1st) {1st};
    \node [block, right= of 1st]  (2nd1) {2nd1};
\begin{scope}[node distance=2mm and 10mm]%Here we change it for everything inside this scope
    \node [block, above= of 2nd1] (2nd2) {2nd2};
    \node [block, below= of 2nd1] (2nd3) {2nd3};
    \node [block, right= of 2nd1] (3rd1) {3rd1};
    \node [block, above= of 3rd1] (3rd2) {3rd2};
    \node [block, above= of 3rd2] (3rd3) {3rd3};
\end{scope}
    \node [block, below= of 3rd1] (3rd4) {3rd4};
    \node [block, below= of 3rd4] (3rd5) {3rd5};

    \path [line] (1st) -- (2nd1);
    \path [line] (2nd1) -- (2nd2);
    \path [line] (2nd1) -- (2nd3);
    \path [line] (2nd2) -- (3rd3);
    \path [line] (2nd1) -- (3rd1);
    \path [line] (1st) -- (2nd1);
\end{tikzpicture}
\end{document}

enter image description here

Best Answer

Related Solutions

[Tex/LaTex] How to create a matrix normal form

[Tex/LaTex] How to define the default vertical distance between nodes

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