R = 8.3145;m = 4;h = 6.626 * 10.^(-34);T6 = 300;P6 = -100:0.1:100;U6 = 3/2 * N * R * T6;H6 = 5/2 * N * R * T6;F6 = - N .* R .* T6 .* (1 + log(R .* T6 ./ P6 .* (2 * pi .* m .* R .* 3 ./ P6 ./ (h ^ 2)).^ 1.5));G6 = - N .* R .* T6 .* (log(R .* T6 ./ P6 .* (2 * pi .* m .* R .* 3 ./ P6 ./ (h ^ 2)).^ 1.5));plot(P6,U6,'r',P6,H6,'b',P6,F6,'y',P6,G6,'k')grid on title (' r: U(P),H(P),F(P),G(P) combine')MATLAB: Why just showing two lines
plot
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You need three values of f(x) in order to completely solve the equation.
Or it can be expressed in terms of the known constants together with the unknown f(0), f(1), f(2)
sum(-((h0 - 1 + R .* h1 + h2 * R.^2) .* f(0) + R .* ((h0 - 1 + R .* h1) .* f(1) + R .* f(2) .* (h0 - 1))) .* (1./R)^x ./ (3 * h3 .* R.^3 + 2 * h2 .* R.^2 + R * h1)where
R = roots([h3, h2, h1, h0-1]);Note: all three roots of R must be included, even if imaginary!
Hello NurFadhilah,
I believe this could be solved by substracting the difference in height between the second and third surfaces from Z2 and Z3. Please see attached screenshot. This could be implemented in the code as shown in variables Z2 and Z3 below.
Z2 = [z9 z12]-0.09031;
Z3 =[z12 z9]-0.09031;
Hope this helps!
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