MATLAB: Randomly generate point satisfying quations

MATLABrandomly generate points

hello, everyone. I wonder if there is any way to randomly generate 50 points satisfying the following equaiton?

Best Answer

If you have symbolic toolbox:

syms x y
eqn = x.^2+(3/2*y-sqrt(abs(x)))^2 == 3;
z(x) = solve(eqn,y);
xrand = rand(1,100); %Some random numbers
yrand = cell2mat(cellfun(@double,z(xrand),'UniformOutput',false));

Related Solutions

MATLAB: How to specify , n ,the number of random integers

 function r = random(x,y) 
 r = round(x + (y-x).*rand); end

 random = @(x,y)randi([x, y])

function r = randomn(x,y,n) 
r = round(x + (y-x).*rand(n,1));

randomn = @(x,y,n)randi([x y],n,1)

randomn = @(x,y,n)arrayfun(@(i1)random(x , y),(1:n)')

MATLAB: How to generate only four normally distributed random numbers with given mean and std. deviation

That's statistics, it only works properly if the sample size is large enough.

With two constraints (mean, and std) only two out of your four numbers are truly random. If you really wanted to, you could generate two random numbers and then solve for the last two:

%generate two random numbers: a,b
%a+b+x+y = 4*mu  %definition of mean, x and y unknown.
%gives: y = (4*mu-a-b) - x (eq. 1)
%(a-mu)^2 + (b-mu)^2 + (x-mu)^2 + (y-mu)^2  = 3*sigma^2 %one of the definition of std, (eq.2)
%substitute y from eq. 1 in eq. 2 and solve quadratic equation for x

Best Answer

Related Solutions

MATLAB: How to specify , n ,the number of random integers

MATLAB: How to generate only four normally distributed random numbers with given mean and std. deviation

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