If we have an equation like G(z)=(2z^3-4.424z^2+3.3634z-0.8721)/(z^4-3.037z^3+3.425z^2-1.6935237z+0.3084332) how do we convert this to w-plane by using bilinear transformation z=(1+w)/(1-w)? Is there a single command or are a set of commands available?
MATLAB: How to convert an equation from z-plane to w-plane in MATLAB
bilinearMATLABw-planez-plane
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MATLAB control system toolbox have d2c function to convert transfer function from discrete (z-domain) to continuous (s-domain). However, you need to specify the sample time period in the discrete domain. Try this
ts = 0.1;z = tf('z', 0.01);Gz = (0.003569*z+0.003395)/(z^2-1.861*z+0.8607);Gw = d2c(G);GzGwResult
Gz = 0.003569 z + 0.003395 ---------------------- z^2 - 1.861 z + 0.8607 Sample time: 0.01 secondsDiscrete-time transfer function.Gw = -2.348e-07 s + 0.7499 --------------------- s^2 + 1.5 s - 0.03231 Continuous-time transfer function.s-domain is equivalent to w-domain when 
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.Your âTâ matrix must become a cell array. See my sample of âTâ for an example.
Once you do that, I would do something like this:
Y = [12.004 13.1573 11.1665 11.8082 12.2129 12.8075 12.4167 11.5708 12.5798 13.7489];T={'cluster2'; 'cluster1'; 'cluster3'; 'cluster9'; 'cluster0'; 'cluster7'; 'cluster4'}; % Sample Of Cell Array
[UnqClust,~,idx] = unique(T); % Unique Values & Locations
Out = Y(idx); % Mapped Output
for k1 = 1:length(idx) fprintf(1, '\t%s\t%.4f\n', T{k1}, Out(k1)) % Demonstration Output (Delete Loop)
end cluster2 11.1665 cluster1 13.1573 cluster3 11.8082 cluster9 12.4167 cluster0 12.0040 cluster7 12.8075 cluster4 12.2129
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