MATLAB: Does the loop only run once

loop

function I=trapezoidal(f,a,b,n)

h=(b-a)/n; % length of the interval

total=0;

x=a;

fa=f;

x=b;

fb=f;

for i=n

x=i;

fn=f+total

total=fn

end

I=fa+fb+2*fn;

end

Best Answer

I assume that your parameter n is a scalar? If you want to let your script loop from 1 through n, you use for i = 1:n.

Related Solutions

MATLAB: Do the loops only run once

Raquel - the MATLAB debugger is helpful in cases like this. If you put a breakpoint in your simpson13 you would notice a problem with the input parameter f. Look closely at how it is being assigned

x=0;
n=6; % n is the number of intervals and must be > 0 and even
a=0; b=pi;% a is the lower bound and b is the upper bound
f=5+13*sin(x); % Function

f is not a function in this case but is a scalar value (5) since x is zero. If you want f to be an anonymous function then you need to assign it as

f = @(x)5+13*sin(x);

where nthe @ operator creates the handle, and the parentheses () immediately after the @ operator include the function input arguments. You will need to change how this function is used in your code as well. For example,

fa=f(a); 
fb=f(b);

etc.

MATLAB: How do you finish this for loop? It is telling me to define the variable “total”, but what do I put in order for it to flow with the loop

total=0;   % you forgot to intialise total ( to define total before usage)
for i = 1:5
 number = input('Enter a number: ');
 total = total + number;
fprintf('The sum of the numbers is %.2f\n', total);
end

Best Answer

Related Solutions

MATLAB: Do the loops only run once

MATLAB: How do you finish this for loop? It is telling me to define the variable “total”, but what do I put in order for it to flow with the loop

Related Question