MATLAB: How do you finish this for loop? It is telling me to define the variable “total”, but what do I put in order for it to flow with the loop

for loopMATLAB

for i = 1:5
 number = input('Enter a number: ');
 total = total + number;
end
fprintf('The sum of the numbers is %.2f\n', total);

Best Answer

total=0;   % you forgot to intialise total ( to define total before usage)
for i = 1:5
 number = input('Enter a number: ');
 total = total + number;
fprintf('The sum of the numbers is %.2f\n', total);
end

Related Solutions

MATLAB: How could I finish the for loop

First thing:

[row,col]=find(stations(i)==stats(1));

This only looks at a single value of stations, so it can only return a single value for row and col. This means that dataps=max(datap(row)); will return every value as max, because it is only comparing one value at a time.

Also, stations is a 1x9 array, so all row values will be 1.

You might try something more like this to get your logic and max values.

for k = 1:length(stats);
 dataps = max(datap(stations==stats(k)));
 datapb=[datapb;dataps];
end

MATLAB: Finishing a calculation

As far as MATLAB is concerned, it has finished the calculations. It has given you exact analytic solutions, rather than mere 16 digit floating point approximations.

I notice that your outputs are complex valued. You need to take extra steps to output complex values properly.

dd = double(d);
fprintf(fid,'%+5.5f %+5.5fi\n', [real(dd(:)), imag(dd(:))].' );

Here the "i" after the "%+5.5f" is just a literal character to indicate the imaginary component.

In the example above it appears that the imaginary component vanishes in practice, which is not at all obvious from casual examination. If that is the situation for all values, then you could use

fprintf(fid,'%+5.5f\n', real(dd(:)) );

but unless you can prove that the imaginaries will vanish, outputting them would be safer.

Best Answer

Related Solutions

MATLAB: How could I finish the for loop

MATLAB: Finishing a calculation

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