MATLAB: 4 Day temperature comparison, including current day

temperature comparisonThingSpeak

How can I include the current day in the 3 day temperature comparison.

[datetime('today')-days(0),datetime('today')], gives an error

Best Answer

You can try to use the last minute of the current day, since it says starting date must be before than ending date

todayDate = datetime('today');
todayDate = todayDate + minutes(1439);
[datetime('today')-days(0),todayDate]

Related Solutions

MATLAB: Hi, i have two dates like 2013_12_28 and 2014_01_06, and i want to calculate the mean date (2014_01_01) which would be in the form of 2014.0014

md = mean(datenum({'2013_12_28', '2014_01_06'}, 'YYYY_mm_dd'));
dv = datevec(md);
days_into_year = md - datenum([dv(1),1,1]);

But once you have days_into_year you have to convert that into a year fraction, which requires careful definition of how long a "year" is. Is a "year" 365 days, always? Is a "year" 365.2421875 days? Is a "year" 365 days for non-leap years but 366 days for leap-years? If so then should it be 365 days for dates in the year before the leap day but 366 for dates on or after the leap day?

Converting to a specific date is much easier, and getting the result in terms of days is easy, but fraction of a year needs clarification.

MATLAB: How to pick data from time range of every day

Here's an example:

d = thingSpeakRead(12397,'NumPoints',8000,'OutputFormat','TimeTable');
t = timerange(today('datetime'),today('datetime')+hours(3));
first3Hr = d(t,:)

Feel free to modify as needed. Also take a look at the documentation for thingSpeakRead, timerange and date/time arithmetic in MATLAB.

Best Answer

Related Solutions

MATLAB: Hi, i have two dates like 2013_12_28 and 2014_01_06, and i want to calculate the mean date (2014_01_01) which would be in the form of 2014.0014

MATLAB: How to pick data from time range of every day

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