[Tex/LaTex] Variable battery1 symbol in circuitikz

circuitikztikz-pgf

Is it possible to produce a variable battery1 sign (battery with one up slanted arrow) in circuitikz? There are options for vR and vL (variable resistor) but not for the battery1. I need it to represent a variable power supply. MWE is appended below

\documentclass{article}
\usepackage{tikz,circuitikz}
\begin{document}
\begin{circuitikz}
 \draw   (0,-2) to[battery1] (2,-2) node [right] {Powersupply};
\end{circuitikz}
\end{document}

Generated from MWE
What I want

I can manually put an up arrow and position it to the middle of battery1 sign but any shortcut like vR or vL would help.

Best Answer

Just define your own component. I copy&pasted the battery1 definition and added the arrow.

\documentclass{article}
\usepackage{tikz,circuitikz}

\makeatletter

\def\pgf@circ@battery2@path#1{\pgf@circ@bipole@path{battery2}{#1}}
\compattikzset{battery2/.style = {\circuitikzbasekey, /tikz/to path=\pgf@circ@battery2@path, \circuitikzbasekey/bipole/is voltage=true, v=#1}}

\ctikzset{bipoles/battery2/height/.initial=.6}
\ctikzset{bipoles/battery2/width/.initial=.3}

\pgfcircdeclarebipole{}{\ctikzvalof{bipoles/battery2/height}}{battery2}{\ctikzvalof{bipoles/battery2/height}}{\ctikzvalof{bipoles/battery2/width}}{
        \pgfpathmoveto{\pgfpoint{.33\pgf@circ@res@right}{0}}
        \pgfpathlineto{\pgfpoint{\pgf@circ@res@right}{0}}
        \pgfpathmoveto{\pgfpoint{.33\pgf@circ@res@left}{0}}
        \pgfpathlineto{\pgfpoint{\pgf@circ@res@left}{0}}
        \pgfusepath{draw}

        \pgfsetlinewidth{\pgfkeysvalueof{/tikz/circuitikz/bipoles/thickness}\pgfstartlinewidth}
        \pgfpathmoveto{\pgfpoint{.33\pgf@circ@res@left}{.5\pgf@circ@res@up}}
        \pgfpathlineto{\pgfpoint{.33\pgf@circ@res@left}{.5\pgf@circ@res@down}}

        \pgfpathmoveto{\pgfpoint{.33\pgf@circ@res@right}{\pgf@circ@res@up}}
        \pgfpathlineto{\pgfpoint{.33\pgf@circ@res@right}{\pgf@circ@res@down}}

        \pgfsetarrowsend{latex'}
        \pgfpathmoveto{\pgfpoint{1.5\pgf@circ@res@left}{0.9\pgf@circ@res@down}}
        \pgfpathlineto{\pgfpoint{1.5\pgf@circ@res@right}{0.9\pgf@circ@res@up}}

        \pgfusepath{draw}
}

\makeatother
\begin{document}
\begin{circuitikz}
 \draw   (0,-2) to[battery2] (2,-2) node [right] {Powersupply};
\end{circuitikz}
\end{document}

Output:

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In the actual question, you only want to be able to mirror the ellipse, and so draw it starting from the negative x-axis (the title of the question suggests a more flexible approach). That's actually not too hard since we can exploit the symmetry of the ellipse. The key is to provide it with a negative x-radius, since then it will start from the negative x-axis (and proceed clockwise, but we could correct for that by negating the y-radius as well). To do this, we interrupt the call from the node shape to the drawing command and flip the sign of the x-radius. The simplest way to do this is to redefine the \pgfpathellipse macro to do the negation and then call the original macro. The following code does this.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations,shapes,decorations.markings}
\makeatletter
\let\origpgfpathellipse=\pgfpathellipse
\def\revpgfpathellipse#1#2#3{%
  #2%
  \pgf@xa=-\pgf@x
  \origpgfpathellipse{#1}{\pgfqpoint{\pgf@xa}{0pt}}{#3}}
\makeatother

\tikzset{
  reversed ellipse/.style={
    ellipse,
    reverse the ellipse%
  },
  reverse the ellipse/.code={
    \let\pgfpathellipse=\revpgfpathellipse
  }
}
\begin{document}
\begin{tikzpicture}
\node[ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,0) {hello world};

\node[reversed ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
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    }
  }
] at (0,-2) {hello world};
\end{tikzpicture}

\end{document}

Here's the result:

rotated ellipse

(the arrow got clipped, but you can see where it lies)

[Tex/LaTex] Circuitikz different ground symbol

The easiest way is to draw the line by yourself, as suggested Thanos. You can also redefine circuitikz ground code or add a new ground symbol. Here is an example:

\documentclass{standalone}
\usepackage{circuitikz}
\makeatletter
\pgfdeclareshape{ground}{
\anchor{center}{
    \pgfpointorigin
}
\behindforegroundpath{      
    \pgf@circ@res@step=\ctikzvalof{monopoles/ground/width}\pgf@circ@Rlen

    \pgfscope       
        \pgfpathmoveto{\pgfpointorigin}
        \pgfpathlineto{\pgfpoint{0pt}{-\pgf@circ@res@step}}
        \pgfusepath{draw}

        \pgfsetlinewidth{6\pgflinewidth} % thickness

        \pgfpathmoveto{\pgfpoint{-\pgf@circ@res@step}{-\pgf@circ@res@step}}
        \pgfpathlineto{\pgfpoint{\pgf@circ@res@step}{-\pgf@circ@res@step}}
        \pgfusepath{draw}                       
    \endpgfscope
    }
}
\makeatother

\begin{document}
\begin{circuitikz}[american voltages]
\draw 
(0,0) node [ground] {}
      to [V] (0,2)
;
\end{circuitikz}
\end{document}

You can change the value in the line with the comment "thickness" even with a natural value (i.e. 3pt).

enter image description here

Best Answer

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

[Tex/LaTex] Circuitikz different ground symbol

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