# [Tex/LaTex] Using \nearrow and \searrow to separate an equation in two alternatives

arraysarrowsequations

I'm tryin' to write the solution of an equation with two possible solutions, as x(ax-a+1)=0. I'm using \nearrow and \searrow with an array but I don't get it fits right. This is the code:

$\rightarrow x(ax-a+1)=0\begin{array}{ll} & {\color{red}{\color{red}x=0}}\\ \nearrow\\ \searrow & ax-a+1=0\rightarrow x=\dfrac{a-1}{a}\rightarrow{\color{red}{\color{red}x=1-\dfrac{1}{a}}} \end{array}$

Instead of fixing your approach, I just show two other possibilities which I would prefer here.

% arara: pdflatex

\documentclass{article}
\usepackage{xcolor}
\usepackage{mathtools}
\usepackage{tikz-cd}

\begin{document}
$\rightarrow x(ax-a+1)=0\rightarrow\begin{dcases} {\color{red}x=0}\\ ax-a+1=0\rightarrow x=\frac{a-1}{a}\rightarrow{\color{red}x=1-\frac{1}{a}} \end{dcases}$

$\begin{tikzcd}[% ,row sep={10,between origins}, column sep=15 ,every arrow/.append style={start anchor=east, end anchor=west} ,/tikz/column 2/.append style={anchor=base west} ] & \color{red}x=0\\ \rightarrow x(ax-a+1)=0 \arrow{ur}\arrow{dr} & \\ & ax-a+1=0\rightarrow x=\dfrac{a-1}{a}\rightarrow{\color{red}x=1-\dfrac{1}{a}} \end{tikzcd}$
\end{document}

The \rightarrow in front of the big brace is not really needed, though.

If you want to separate the arrows in my second example, you can do something like \arrow[shorten <= 1mm]{ur}\arrow[shorten <= 1mm]{dr} or you add some yshift to their start anchors.