It seems that for a given height, the \sqrt symbol "switches" it's type, and it becomes vertical at some part, like here:
But I want it to be like the second one. What is the solution for this?
EDIT: I've cut this line out of my .tex file. It looks like this:
\documentclass[12pt]{article}
\usepackage{enumerate}
\usepackage{lmodern}
\usepackage{amsmath}
\begin{document}
\begin{enumerate}[1.]
\item[\textbf{MO:}] {}
\begin{enumerate}[a)]
\item{
$$\lim \limits_{k \to \infty}
\sqrt{\frac{1+(-1)^k}{3+\dfrac{1}{k^2}+\dfrac{8}{k^3}}}=
\sqrt{\dfrac{1+1}{3+0+0}}=\sqrt{\dfrac{2}{3}}$$}
\end{enumerate}
\end{enumerate}
\end{document}
Best Answer
EDITED to provide second cut (with optional argument for fine-tuning the vertical height of the scaled root symbol). What I do here is take a standard size sqrt sign and stretch it vertically to match the height of its argument, using the
scalerel
package. The fine-tuning of the height is done with thestackengine
package.