[Tex/LaTex] multiple choice questions type setting querries

exam

enter image description here

I need to have four different question papers in which the order of the above questions only changed and i need to give the answer for the respective question paper in a separate sheet. so kindly help me to prepare those question papers from this. That i need to prepare another question paper by shuffling the questions and i need to give the answer respectively. How should i do?

 \documentclass[12pt,a4paper]{exam}
    \usepackage{amsmath,amsthm,amsfonts,amssymb,dsfont}
    \setlength\parindent{0pt}
        %usage \choice{ }{ }{ }{ }
        %(A)(B)(C)(D)
        \newcommand{\fourch}[4]{
        \par
                \begin{tabular}{*{4}{@{}p{0.23\textwidth}}}
                (a)~#1 & (b)~#2 & (c)~#3 & (d)~#4
                \end{tabular}
        }

        %(A)(B)
        %(C)(D)
        \newcommand{\twoch}[4]{

                \begin{tabular}{*{2}{@{}p{0.46\textwidth}}}
                (a)~#1 & (b)~#2
                \end{tabular}
        \par
                \begin{tabular}{*{2}{@{}p{0.46\textwidth}}}
                (c)~#3 & (d)~#4
                \end{tabular}
        }

        %(A)
        %(B)
        %(C)
        %(D)
        \newcommand{\onech}[4]{
        \par
              (a)~#1 \par (b)~#2 \par (c)~#3 \par (d)~#4
        }

        \newlength\widthcha
        \newlength\widthchb
        \newlength\widthchc
        \newlength\widthchd
        \newlength\widthch
        \newlength\tabmaxwidth

        \setlength\tabmaxwidth{0.96\textwidth}
        \newlength\fourthtabwidth
        \setlength\fourthtabwidth{0.25\textwidth}
        \newlength\halftabwidth
        \setlength\halftabwidth{0.5\textwidth}

      \newcommand{\choice}[4]{%
      \settowidth\widthcha{AM.#1}\setlength{\widthch}{\widthcha}%
      \settowidth\widthchb{BM.#2}%
      \ifdim\widthch<\widthchb\relax\setlength{\widthch}{\widthchb}\fi%
      \settowidth\widthchb{CM.#3}%
      \ifdim\widthch<\widthchb\relax\setlength{\widthch}{\widthchb}\fi%
      \settowidth\widthchb{DM.#4}%
      \ifdim\widthch<\widthchb\relax\setlength{\widthch}{\widthchb}\fi%
      \ifdim\widthch<\fourthtabwidth
        \fourch{#1}{#2}{#3}{#4}
      \else\ifdim\widthch<\halftabwidth
        \ifdim\widthch>\fourthtabwidth
          \twoch{#1}{#2}{#3}{#4}
        \else
          \onech{#1}{#2}{#3}{#4}
        \fi
      \fi\fi
    }
    \begin{document}
     \begin{questions}
    \question If $a = 3 + i$ and $z = 2 - 3i$ then the points on the Argand diagram
    representing az, 3az and - az are
    \choice{Vertices of a right angled triangle}{ Vertices of an equilateral 
    triangle}{Vertices of an isosceles triangle}{Collinear}
    \question If z represents a complex number then $\arg (z) + \arg\left(\bar z\right)$ is 
    \choice{$\dfrac{\pi}{4}$}{$\dfrac{\pi}{2}$}{0}{$\dfrac{\pi}{6}$}
    \question If the amplitude of a complex number is $\dfrac{\pi}{2}$ then the number is
    \choice{ purely imaginary}{purely real}{0}{neither real nor imaginary}
    \question The value of $i + i^{22} + i^{23} + i^{24} + i^{25}$ is
    \choice{i}{-i}{1}{-1}
    \question The volume generated by 
    rotating the triangle with vertices at
    (0, 0), (3, 0) and (3, 3) about x-axis is
    \choice{$18\pi$}{$2\pi$}{$36\pi$}{$9\pi$}\end{questions}
    \end{document}

    \end{document}

one more question ##

If i want to shuffle the question to prepare four different questions papers having same questions but with the different question numbers what should i do…??

that is i need to mark the question paper given above as Code A. and i need to print another question paper which marked as Code-B and in this question paper the first question code-A should be in question number 5 and similarly others also should have different positions…

thank you for your help in advance…

Best Answer

I incorporated this answer to solve your problem. After you write your four choices, put the correct choice (a, b, c, etc.) in braces as a fifth choice.

\documentclass[12pt,a4paper]{exam}
\usepackage{amsmath,amsthm,amsfonts,amssymb,dsfont}
\usepackage{ifthen}

% Accumulate the answers. Unmodified from Phil Hirschorn's answer
% https://tex.stackexchange.com/questions/15350/showing-solutions-of-the-questions-separately/15353
\newbox\allanswers
\setbox\allanswers=\vbox{}

\newenvironment{answer}
{%
    \global\setbox\allanswers=\vbox\bgroup
    \unvbox\allanswers
}%
{%
    \bigbreak
    \egroup
}

\newcommand{\showallanswers}{\par\unvbox\allanswers}
% End Phil's answer


% Is there a better way?
\newcommand*{\getanswer}[5]{%
    \ifthenelse{\equal{#5}{a}}
    {\begin{answer}\thequestion. (a)~#1\end{answer}}
    {\ifthenelse{\equal{#5}{b}}
        {\begin{answer}\thequestion. (b)~#2\end{answer}}
        {\ifthenelse{\equal{#5}{c}}
            {\begin{answer}\thequestion. (c)~#3\end{answer}}
            {\ifthenelse{\equal{#5}{d}}
                {\begin{answer}\thequestion. (d)~#4\end{answer}}
                {\begin{answer}\textbf{\thequestion. (#5)~Invalid answer choice.}\end{answer}}}}}
}

\setlength\parindent{0pt}
%usage \choice{ }{ }{ }{ }
%(A)(B)(C)(D)
\newcommand{\fourch}[5]{
    \par
    \begin{tabular}{*{4}{@{}p{0.23\textwidth}}}
        (a)~#1 & (b)~#2 & (c)~#3 & (d)~#4
    \end{tabular}
    \getanswer{#1}{#2}{#3}{#4}{#5}
}

%(A)(B)
%(C)(D)
\newcommand{\twoch}[5]{
    \par
    \begin{tabular}{*{2}{@{}p{0.46\textwidth}}}
        (a)~#1 & (b)~#2
    \end{tabular}
    \par
    \begin{tabular}{*{2}{@{}p{0.46\textwidth}}}
        (c)~#3 & (d)~#4
    \end{tabular}
    \getanswer{#1}{#2}{#3}{#4}{#5}
}

%(A)
%(B)
%(C)
%(D)
\newcommand{\onech}[5]{
    \par
    (a)~#1 \par (b)~#2 \par (c)~#3 \par (d)~#4
    \getanswer{#1}{#2}{#3}{#4}{#5}
}

\newlength\widthcha
\newlength\widthchb
\newlength\widthchc
\newlength\widthchd
\newlength\widthch
\newlength\tabmaxwidth

\setlength\tabmaxwidth{0.96\textwidth}
\newlength\fourthtabwidth
\setlength\fourthtabwidth{0.25\textwidth}
\newlength\halftabwidth
\setlength\halftabwidth{0.5\textwidth}

\newcommand{\choice}[5]{%
\settowidth\widthcha{AM.#1}\setlength{\widthch}{\widthcha}%
\settowidth\widthchb{BM.#2}%
\ifdim\widthch<\widthchb\relax\setlength{\widthch}{\widthchb}\fi%
    \settowidth\widthchb{CM.#3}%
\ifdim\widthch<\widthchb\relax\setlength{\widthch}{\widthchb}\fi%
    \settowidth\widthchb{DM.#4}%
\ifdim\widthch<\widthchb\relax\setlength{\widthch}{\widthchb}\fi%

% These if statements were bypassing the \onech option.
% \ifdim\widthch<\fourthtabwidth
%     \fourch{#1}{#2}{#3}{#4}{#5}
% \else\ifdim\widthch<\halftabwidth
% \ifdim\widthch>\fourthtabwidth
%     \twoch{#1}{#2}{#3}{#4}{#5}
% \else
%      \onech{#1}{#2}{#3}{#4}{#5}
%  \fi\fi\fi}

% Allows for the \onech option.
\ifdim\widthch>\halftabwidth
    \onech{#1}{#2}{#3}{#4}{#5}
\else\ifdim\widthch<\halftabwidth
\ifdim\widthch>\fourthtabwidth
    \twoch{#1}{#2}{#3}{#4}{#5}
\else
    \fourch{#1}{#2}{#3}{#4}{#5}
\fi\fi\fi}



\begin{document}
\begin{questions}

\question If $a = 3 + i$ and $z = 2 - 3i$ then the points on the Argand diagram representing az, 3az and - az are
\choice{Vertices of a right angled triangle}{Vertices of an equilateral triangle}{Vertices of an isosceles triangle}{Collinear}{a}

\question If z represents a complex number then $\arg (z) + \arg\left(\bar z\right)$ is 
\choice{$\dfrac{\pi}{4}$}{$\dfrac{\pi}{2}$}{0}{$\dfrac{\pi}{6}$}{b}

\question If the amplitude of a complex number is $\dfrac{\pi}{2}$ then the number is
\choice{purely imaginary}{purely real}{0}{neither real nor imaginary}{a}

\question The value of $i + i^{22} + i^{23} + i^{24} + i^{25}$ is
\choice{i}{-i}{1}{-1}{c}

\question The volume generated by rotating the triangle with vertices at (0, 0), (3, 0) and (3, 3) about x-axis is
\choice{$18\pi$}{$2\pi$}{$36\pi$}{$9\pi$}{a}

\question To complete the song, the last answer should be
\choice{a}{b}{c}{d}{e} % Invalid answer choice


\question To complete the song, the last answer should be 
\choice{a long tex a long tex a long tex a long tex a long tex a long tex a long tex a long tex a long tex}{b}{c}{d}{a} 
\end{questions}

%\newpage  %Uncomment to put on new age
\bigskip
Answer Key:
\bigskip  
\showallanswers % Phil Hirschorn

\end{document}

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Related Solutions

[Tex/LaTex] Print answer key to multiple choice questions

You could update \CorrectChoice to insert an incremental \label. However, this would mean that only the most recent \CorrectChoice would be returned through a \theCorrectChoice call:

enter image description here

\documentclass{exam}% http://ctan.org/pkg/exam

\newcounter{correctchoicemark}% Counter to keep track of correct choice mark
\newcommand{\theCorrectChoice}{\ref{correctchoice-\thecorrectchoicemark}}% Print correct choice
\renewcommand{\choiceshook}{% Adapt \CorrectChoice to insert \label
  \let\oldCorrectChoice\CorrectChoice% Store \CorrectChoice in \oldCorrectChoice
  \renewcommand{\CorrectChoice}{%
    \oldCorrectChoice% Original \CorrectChoice
    \stepcounter{correctchoicemark}% Increment correct choice mark
    \label{correctchoice-\thecorrectchoicemark}% \label original \CorrectChoice
  }%
}
\let\oldoneparchoices\oneparchoices
\renewcommand{\oneparchoices}{%
  \oldoneparchoices% Original oneparchoices environment start
  \let\oldCorrectChoice\CorrectChoice% Store \CorrectChoice in \oldCorrectChoice
  \renewcommand{\CorrectChoice}{%
    \oldCorrectChoice% Original \CorrectChoice
    \stepcounter{correctchoicemark}% Increment correct choice mark
    \label{correctchoice-\thecorrectchoicemark}% \label original \CorrectChoice
  }%
}
\begin{document}

\begin{questions}

  \question This is a multiple choice question
  \begin{choices}
    \choice this is a choice
    \choice this is another choice
    \CorrectChoice this is the correct choice
    \choice this is another choice
  \end{choices}

  The answer is \theCorrectChoice.

  \question This is a multiple choice question
  \begin{oneparchoices}
    \choice this is a choice
    \CorrectChoice this is another choice
    \choice this is the correct choice
    \choice this is another choice
  \end{oneparchoices}

  The answer is \theCorrectChoice.

\end{questions}

\end{document}

exam provides a hook into the choices environment via \choiceshook. Updating this to redefine \CorrectChoice is one (clean) way of inserting the appropriate code to obtain a \label you can \reference. oneparchoices does not provide this hook, so a different method altogether is employed in order to redefine \CorrectChoice.

More work is required for this solution to work correctly with hyperref.

[Tex/LaTex] Multiple Choice Questions in Exam package

1) I used xpatch to fix the amount of space after each choice.

2) I renewed the \questionlabel command for the first question. \phantom{} reserves the space of the question number but it is not printed. I reset it it back to the class default before the section question.

\documentclass[addpoints]{exam}
\usepackage{xpatch}

% Need both to patch both instances (choice, correctchoice) in the oneparchoices environment.
% Unless there is a global replacement that works within an environment. I don't know.
% Replaces \hskip 1em with \hfill
\xpatchcmd{\oneparchoices}{\penalty -50\hskip 1em plus 1em\relax}{\hfill}{}{}
\xpatchcmd{\oneparchoices}{\penalty -50\hskip 1em plus 1em\relax}{\hfill}{}{}

\begin{document}
\begin{center}
\gradetable
\end{center}
\begin{questions}

\renewcommand\questionlabel{\phantom{\thequestion.}}
\titledquestion{\textbf{Multiple Choice}}[10]
What is the Capital of the United States in 1799?

\begin{oneparchoices}
\choice NY
\CorrectChoice Washington D.C.
\choice Chicago
\choice LA
\end{oneparchoices}

\renewcommand\questionlabel{\thequestion.}
%\setcounter{question}{0}   %Uncomment if you want the first numbered question to start at 1.

\question[10]
What is the Capital of the United Kinddom in 1999?

\begin{oneparchoices}
\choice London 
\CorrectChoice Washington D.C.
\choice Chicago
\choice Los Angeles
\end{oneparchoices}

\end{questions}
\end{document}

enter image description here

one more question ##

Best Answer

Related Solutions

[Tex/LaTex] Print answer key to multiple choice questions

[Tex/LaTex] Multiple Choice Questions in Exam package

Related Question