I want to find the LaTeX symbol for the character shown in the attached image.
I have tried \mathcal{J}, \jmath, \textctj, \mathscr{J}, and \mathfrak{J}, but none of them worked.
[Tex/LaTex] How to typeset this letter in LaTeX
symbols
Related Solutions
The following example constructs the symbol in the following way:
- The top part with the round line end of the vertical bar is used as branch line.
- The length of the branch is the same as in the plus symbol. But the length can
be changed by redefining
\UpDownYFactorto a value different than1. - The intersection point is the same as in the plus symbol at the mathematical center axis.
- The symbol adopts in size to the current math style.
- The side bearings have the same width as in the plus symbol.
- The names for the provided symbols are the same as in package
MnSymbol:\upYand\downY. - The symbols act as binary operators. It can be changed by replacing
\mathbin.
Example file:
\documentclass{article}
\usepackage{graphicx}
\usepackage{trimclip}
\makeatletter
\providecommand*{\upY}{%
\mathbin{%
\mathpalette\@updownY{0}%
}%
}
\providecommand*{\downY}{%
\mathbin{%
\mathpalette\@updownY{1}%
}%
}
\providecommand*{\UpDownYFactor}{1}
\newcommand*{\@updownY}[2]{%
% #1: math style
% #2: 0 = up, 1 = down
\sbox0{$#1+\m@th$}%
\dimen2=.5\dimexpr\wd0-\ht0-\dp0\relax
% => \dimen2: side bearing
\sbox2{$#1\vcenter{}$}%
\dimen4=\dimexpr\ht0-\ht2\relax
% => \dimen4: branch length
\setbox0=\hbox to 0pt{%
\hss
\clipbox{%
0pt %
{\dimexpr\totalheight-\UpDownYFactor\dimen4\relax} %
0pt %
-\dimen2%
}{$#1|$}%
\hss
}%
\ht0=\dimexpr\ht0-\dimen2\relax
\kern\dimen2 %
\raise\ht2\hbox{%
\ifnum#2=0 %
{\rotatebox{120}{\copy0}}%
\copy0 %
{\rotatebox{-120}{\copy0}}%
\else
{\rotatebox{60}{\copy0}}%
{\rotatebox{180}{\copy0}}%
{\rotatebox{-60}{\copy0}}%
\fi
}%
\kern\dimen2 %
}
\makeatother
\begin{document}
\[\begin{array}{c}
a \upY b \downY c
\\
\scriptstyle
a \upY b \downY c
\\
\scriptscriptstyle
a \upY b \downY c
\\
\rlap{$\upY$}{\downY}
\end{array}\]
\end{document}
For analyzing the center:
\usepackage{pdfrender}
...
\[
\rlap{%
\sbox0{$\vcenter{}$}%
\sbox2{${\upY}{\downY}{\upY}$}%
\raise\ht0\hbox{\vrule height.01pt depth.01pt width\wd2}%
}%
\pdfrender{TextRenderingMode=Stroke, LineWidth=.01pt}
{\upY}\rlap{$\upY$}{\downY}{\downY}
\]
I would imagine that if font samples are viewable, they're in the public domain. As such, a search for font with spiral symbol yields a host of ideas.
Below I've used the Altemus Spirals Regular font's PDF sample:
Then you can clip out the element you're interested in:
\documentclass{article}
\usepackage{graphicx}
\newcommand{\spiral}[1][]{\includegraphics[
height=.7\baselineskip,
origin=c,% For rotation purposes, rotate around centre
viewport=154mm 173mm 176mm 194mm,clip,
#1% Any other graphicx options
]{altemus_spiral_regular}%
}
\begin{document}
{\setlength{\fboxsep}{0pt}\fbox{\spiral}}
\spiral{}
\spiral[angle=90]
\reflectbox{\spiral}
A regular \spiral{} together with text and even \spiral[angle=180] rotated.
\end{document}
Alternatively, if you have access to a font containing a spiral, you can use XeLaTeX or LauLaTeX directly.
Best Answer
You need to access the "Euler" "math-script" symbols. One way to do so is to load the mathalfa package -- the spelling "mathalpha" is also valid -- with the option
scr=euler.Among font afficionados, Euler script letters (created by the late Hermann Zapf) are known for being almost perfectly upright. This in stark contrast to most other math-script letters, which tend to be moderately or even heavily sloped.