[Tex/LaTex] Double subscript and superscript

subscripts

I have tried several approach and search for similar cases but I couldn't make this working.
enter image description here

As you can see the highlighted yellow looks improper and wrong. I would like to fix the following issues

1) make the subscript and superscript smaller

2) remove the space between sigma and its subscript

3) when i add sigma with subscript beta in the denominator they look like multiplication

I used the following code

$\beta_1,\frac{\sigma^2_{\epsilon}}{S_{xx}}$ and $\sigma^2_{\beta_i}$ and $\frac{\hat{\beta}_i-\beta_i}{\sigma_{\beta_i}}$

I tried using the below code but didn't work also.

\usepackage{lmodern}

\DeclareMathSizes{7}{7}{5}{4} % \scriptsize is 7 pt

\DeclareMathSizes{10}{5}{2}{1} % \tiny is 5 pt  {S}{t}{s}{ss}

Best Answer

I'm inferring that you're not happy with the basic "look" because you would like the subscripts of \sigma to be less far away, i.e, they should be snugged up to the left. If this is the concern, just write \sigma_{\!\beta_1}, \sigma_{\!\beta_1}, etc.

You may also want to settle on a standard size for the fraction terms. In your screenshot \frac (or \dfrac) appears to be employed for the left-hand material, whereas \tfrac appears to be used for the material to the right of \Rightarrow. I would choose one or the other look, but not mix 'em up in one and the same equation. Speaking for myself, I prefer \frac look (with larger parentheses) to the \tfrac look (with smaller parentheses).

enter image description here

\documentclass{article}
\usepackage{amsmath}
\begin{document} 
%% look 1: \tfrac and \big parentheses
\begin{alignat*}{2}
\hat{\beta}_1 &\sim N\bigl(\beta_1,\tfrac{\sigma^2_{\!\epsilon}}{S_{xx}}\bigr) \sim N(\beta_1,\sigma^2_{\!\beta_1})
&&\Rightarrow \tfrac{\hat{\beta}_1-\beta_1}{\sigma^{}_{\!\beta_1}}
=\tfrac{\hat{\beta}_1-\beta_1}{\sigma^{}_{\!\epsilon}/\sqrt{S_{xx}}} \sim N(0,1)\\
\hat{\beta}_0 &\sim N\bigl(\beta_0,\sigma^2_{\!\epsilon} \bigl[\tfrac{1}{n}+\tfrac{\bar{X}^2}{S_{xx}}\bigr]\bigr)
\sim N(\beta_1,\sigma^2_{\!\beta_0})
&&\Rightarrow \tfrac{\hat{\beta}_0-\beta_0}{\sigma^{}_{\!\beta_1}}
=\tfrac{\hat{\beta}_0-\beta_0}{\sigma^{}_{\!\epsilon} 
\sqrt{\frac{1}{n}+\frac{\bar{X}^2}{S_{xx}}}}
\sim N(0,1)
\end{alignat*}

%% look 2: \frac and \bigg parentheses
\begin{alignat*}{2}
\hat{\beta}_1 &\sim N\biggl(\beta_1,\frac{\sigma^2_{\!\epsilon}}{S_{xx}}\biggr) \sim N(\beta_1,\sigma^2_{\!\beta_1})
&&\Rightarrow \frac{\hat{\beta}_1-\beta_1}{\sigma^{}_{\!\beta_1}}
=\frac{\hat{\beta}_1-\beta_1}{\sigma^{}_{\!\epsilon}/\sqrt{S_{xx}}} \sim N(0,1)\\
\hat{\beta}_0 &\sim N\biggl(\beta_0,\sigma^2_{\!\epsilon} \biggl[\frac{1}{n}+\frac{\bar{X}^2}{S_{xx}}\biggr]\biggr)
\sim N(\beta_1,\sigma^2_{\!\beta_0})
&&\Rightarrow \frac{\hat{\beta}_0-\beta_0}{\sigma^{}_{\!\beta_1}}
=\frac{\hat{\beta}_0-\beta_0}{\sigma^{}_{\!\epsilon} 
\sqrt{\frac{1}{n}+\frac{\bar{X}^2}{S_{xx}}}}
\sim N(0,1)
\end{alignat*}
\end{document}
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