circuitikz
So I'm trying to draw the following circuit (Which looks like a half adder) using circuitikz.
However, my code is producing the below diagram.
\begin{circuitikz}
\draw (0, 4)node[xor port] (xorone){}
(0, 2)node[and port] (and){}
(xorone.in 1) node[left=0.5cm](a) {A}
(xorone.in 2) node[left=0.5cm](b) {B}
(a) -| (xorone.in 1)
(b) -| (xorone.in 2)
(a) -| (and.in 1)
(b) -| (and.in 2);
\end{circuitikz}
Is there any way I can make the two wires connecting the gates in 'parallel' not overlap?
You cannot have numbers in macro names (at least not without some trickery).
The following works fine:
\documentclass{article}
\usepackage{circuitikz}
\begin{document}
\newcommand\opampfive[5]
{
\begin{circuitikz}
\draw (0,0) node[op amp] (opamp) {};
\draw (-2,-0.49) to[short, o-] (opamp.+) (-2.2,-0.49) node[anchor=east] {${#1}$};
\draw (-2,0.49) to[short, o-] (opamp.-) (-2.2,0.49) node[anchor=east] {${#2}$};
\draw (-0.08,1.5) to[short, o-] (opamp.up) (-0.08,1.6) node[anchor=south] {${#3}$};
\draw (-0.08,-1.5) to[short, o-] (opamp.down) (-0.08,-1.6) node[anchor=north] {${#5}$};
\draw (1,0) to[short, -o] (2,0) -- (opamp.out) (2.1,0) node[anchor=west] {${#4}$};
\end{circuitikz}
}
\opampfive{1}{2}{3}{4}{5}
\end{document}
The diagram would be improved alot by using connecting wires that are only horizontal or vertical. There is a conveient syntax |- for a path that is first vertical then horizontal, and the corresponding -|. You can apply colours to the individual symbols and to the connecting wires by specifying color=red. Perhaps this is close to what you are after:
\documentclass{beamer}
\usepackage{circuitikz}
\begin{document}
\begin{frame}
\begin{figure}
\centering
\begin{circuitikz} \draw
(0,0) node[not port] (not1) {}
(0,2) node[xor port] (xor1) {}
(0,4) node[and port] (and1) {}
(2,3) node[nor port,color=red] (nor1) {}
(4,1) node[xor port,color=red] (xor2) {}
(6,3) node[or port,color=red] (or1) {}
(6,1) node[and port] (and2) {}
(nor1.in 1) node[above](f) {U}
(nor1.in 2) node[below](g) {U}
(xor2.in 1) node[left](h) {U}
(xor2.in 2) node[left](i) {U}
(or1.out) node[right](j) {U};
\draw[color=red] (and1.out) |- (nor1.in 1)
(xor1.out) |- (nor1.in 2)
(nor1.out) -| (xor2.in 1)
(not1.out) -| (xor2.in 2)
(xor2.out) |- (or1.in 2);
\draw
(and1.out) -- +(4,0) |- (or1.in 1)
(xor1.out) -| (and2.in 1)
(not1.out) -| (and2.in 2);
\end{circuitikz}
\end{figure}
\end{frame}
\end{document}
As the symbols are one unit, you can not (easily) change the colour an input wire right up to the symbol body.
Best Answer
Usually one adds branch points where wires connect, either with
to[short,o-*]ornode[circ]andnode[ocirc]. I specified point(branch)midway between(b.east)and(xorone.in 2).Note: circuitikz always loads the calc library.