[Tex/LaTex] Defining a \newcommand for environment in CircuiTikz

circuitikzmacrostikz-pgf

I have made the following macro for an op-amp with open connectors in circuitikz:

\newenvironment{opamp5}[5]
{
\begin{circuitikz}
\draw (0,0) node[op amp] (opamp) {};
\draw (-2,-0.49) to[short, o-] (opamp.+) (-2.2,-0.49) node[anchor=east] {${#1}$};
\draw (-2,0.49) to[short, o-] (opamp.-) (-2.2,0.49) node[anchor=east] {${#2}$};
\draw (-0.08,1.5) to[short, o-] (opamp.up) (-0.08,1.6) node[anchor=south] {${#3}$};
\draw (-0.08,-1.5) to[short, o-] (opamp.down) (-0.08,-1.6) node[anchor=north] {${#5}$};
\draw (1,0) to[short, -o] (2,0) -- (opamp.out) (2.1,0) node[anchor=west] {${#4}$};
\end{circuitikz}
}

To draw an op-amp with labels, starting from the positive input terminal and moving clockwise to the negative Vcc terminal you simply enter the environment opamp5 as I have defined above:

\begin{opamp5}
{1}{2}{3}{4}{5}
\end{opamp5}

My question is, instead of making this circuitikz picture an environment, is there any way I can define it as a command so i can link to other elements of a circuit diagram? I tried using the same syntax and defining it as \newcommand instead, but LaTeX did not like that. My goal is to have various new commands that I can link together smoothly instead of drawing an op-amp manually each time I need one in a circuit diagram. Rather than having to begin and end an environment, it is much more convenient if I can have a shorter syntax that will produce the same picture.

Thanks

Best Answer

You cannot have numbers in macro names (at least not without some trickery).

The following works fine:

\documentclass{article}
\usepackage{circuitikz}

\begin{document}

\newcommand\opampfive[5]
{
\begin{circuitikz}
\draw (0,0) node[op amp] (opamp) {};
\draw (-2,-0.49) to[short, o-] (opamp.+) (-2.2,-0.49) node[anchor=east] {${#1}$};
\draw (-2,0.49) to[short, o-] (opamp.-) (-2.2,0.49) node[anchor=east] {${#2}$};
\draw (-0.08,1.5) to[short, o-] (opamp.up) (-0.08,1.6) node[anchor=south] {${#3}$};
\draw (-0.08,-1.5) to[short, o-] (opamp.down) (-0.08,-1.6) node[anchor=north] {${#5}$};
\draw (1,0) to[short, -o] (2,0) -- (opamp.out) (2.1,0) node[anchor=west] {${#4}$};
\end{circuitikz}
}

\opampfive{1}{2}{3}{4}{5}
\end{document}

Related Solutions

[Tex/LaTex] how to draw a diagram that forks out, then joins in the middle then forks out again

In addition to the solution suggested by @Qrrbrbirlbel in the comments, playing around a little bit with \usetikzlibrary{positioning}, defining some \node's in the trees that you had already provided, and using \coordinate allows you to get the output that you want.

It might not be the most elegant way to do so, but as has already been pointed out in the comments, this is not really one tree.

\documentclass{article}
\usepackage{tikz}
\usepackage{tikz-qtree}
\usetikzlibrary{positioning}

\begin{document}

\tikzset{font=\small,
         edge from parent path={(\tikzparentnode.south) -- +(0,-8pt) -| (\tikzchildnode)}}

\begin{tikzpicture}
    \Tree [.A
             [.\node(B){B}; ]
             [.\node(C){C}; ]
          ]
\begin{scope}[xshift=0in,yshift=-2cm]
    \Tree [.\node(D){D};
             [.E ]
             [.F ]
          ]
\end{scope}

\coordinate [above=.2cm of D] (D') {};
\draw[-] (B) |- (D');
\draw[-] (C) |- (D');
\draw[-] (D') -- (D);
\end{tikzpicture}

\end{document}

enter image description here

[Tex/LaTex] Tikz obtain node coordinates

An alternative: use of orthogonal coordinate

(p -| q) refers to the point horizontally aligned with p and vertically aligned with q. The -| was chosen in such a way that it's easy to remember which is which; the - side is horizontal, and the | side is vertical. The CircuiTikz manual has further information.

Complete Examples:

Resulting Diagram

Code:

\documentclass[border=10pt,varwidth]{standalone}  
\usepackage{tikz}
\usepackage[american,siunitx]{circuitikz}
\usetikzlibrary{calc,positioning}
\begin{document}

An alternative solution

\begin{circuitikz}  
\draw
(0,0) node[op amp](opamp){}
(opamp.out) to[short,*-o] (2,0)node[]{} node[right]{$v_{out}$};
\draw (opamp.-) -- ++(-0.2,0) to[R,l_=$R_1$] ++ (-2,0)node[ground,rotate=-90]{};
\draw (opamp.+) to[short,-o] ++ (-0.5,0)node[left]{$V_{in}$};

\draw (opamp.-) to [short,*-] ++(0,1) node{} to [R,l=$R_2$] ([yshift=1cm]opamp.- -|opamp.out);
\end{circuitikz}

\medskip

@Astrinus' solution

\begin{circuitikz}
\draw
(0,0) node[op amp](opamp){}
(opamp.out) to[short,*-o] (2,0)node[]{} node[right]{$v_{out}$};

\draw (opamp.-) -- ++(-0.2,0) to[R,l_=$R_1$] ++ (-2,0)node[ground,rotate=-90]{};
\draw (opamp.+) to[short,-o] ++ (-0.5,0)node[left]{$V_{in}$};

\draw let \p1=(opamp.out),\p2=(opamp.-) in (opamp.-) to [short,*-] ++(0,1) 
node{} to [R,l=$R_2$] ++($(\x1,0)-(\x2,0)$);
\end{circuitikz}

\end{document}