I have this pgfplots
plot and I want every single graph to have a different color. A gradient from red to blue or something else (m=2
should be red
, m=11
should be blue
and all the other m
should be between this).
I need this to work even when I change the amount of graphs.
I already tried to transfer the code lines from this example, but I can't get it working: Plotting a graph with several values of a parameter
The minimum working example is added below.
Thank you.
\documentclass[12pt]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{graphicx}
\usepackage{pgfplots}
\pgfplotsset{compat=newest}
\pgfplotsset{
gainplot/.style={
axis x line*=box,
xmax=10,
xmin=0.1,
xmode=log,
width=14cm,
xlabel=$F_\textup{x}$,
xticklabel style={yshift=-0.2cm,},
xtick={0.1,1.0,10.0},
xticklabels={{$0.1$},{$1.0$},{$10.0$}},
axis y line*=box,
ymax=3,
ymin=0,
ymode=normal,
height=7cm,
ylabel=$K$,
yticklabel style={xshift=-0.2cm,},
ytick={0,1,2,3 },
yticklabels={{$0$},{$1$},{$2$},{$3$}},
grid = both,
grid style={line width=0.2pt,},
legend style={
font=\scriptsize,
at={(0.5,1.03)},
anchor=south,
draw=none,
},
legend columns=5,
},
gainplot/.belongs to family=/pgfplots/scale,
}
\pgfmathdeclarefunction{gaincurve}{2}{%
\pgfmathparse{%
(x^2*(#2-1)/(sqrt((#2*x^2-1)^2+x^2*(x^2-1)^2*(#2-1)^2*#1^2)))
}%
}
\tikzstyle{gaincurvestyle}=[
smooth,
%thick,
mark=none,
domain=0.1:10,
samples=100,
]
\begin{document}
\begin{figure}[]
\centering
\begin{tikzpicture}
\begin{axis}[gainplot]
\foreach \m in {2,3,...,11}{
\addplot[gaincurvestyle,red]{gaincurve(0.2,\m)}; %%% Here help is needed.
\addlegendentryexpanded{$m=\m$}
}
\end{axis}
\end{tikzpicture}
\caption{Placeholder.}
\end{figure}
\end{document}
Best Answer
You can use the
\edef
trick mentioned in thepgfplots
manual, combined withevaluate
in the\foreach
, and thered!<value>!blue
color syntax.If you want to normalize based on the values of the loop, you can use
and then set the color of the plot to
red!\redfrac!blue
. For example, if the lowest value in the loop is 2 and the highest is 11, as in your example, you use(\m-2)*100/(11-2)
.If you instead want to normalize based on the index of the loop, you can do
For example, if you're looping over a list of 15 values, use
\i*100/15
. In both cases, it's just a matter of normalizing a value so that it runs from 0 to 100.