[Tex/LaTex] Adjust the size of fit nodes in tikz

fittikz-pgf

I have a problem with controlling the size of fit nodes in tikzpicture. I want the fit node to cover all the area but it does not seem to be working. I searched around but I have not found the solution yet. I would like to ask for your help. Thank you very much. Below is the tex of the figure. I also the image illustrating the wanted target.

\documentclass{article}
\usepackage{forest}
\usetikzlibrary{shapes,positioning}

\begin{document}
% Define the flowchart
\tikzstyle{startstop} = [draw, rounded rectangle, text centered, draw=black]
\tikzstyle{io} = [trapezium, trapezium left angle=70, trapezium right angle=110, text centered, draw=black]
\tikzstyle{process} = [rectangle,inner sep=-0.1ex, minimum height=1cm, text centered, text width=4cm, draw=black]
\tikzstyle{decision} = [diamond, aspect=2, inner sep=-1ex,  text centered, text width=4cm,  draw=black]
\tikzstyle{arrow} = [thick,->,>=stealth, rounded corners]
\begin{figure}[!htb]
\centering
\begin{tikzpicture}[node distance=1.4cm]
\node (start) [startstop] {Start};
\node (in1) [io, below = 0.5 of start, align= center] {$V$: an input sample vector \\ $\alpha$: a user-specified number};
\node (pro1) [process, below of=in1] {Do something};
\node (pro2) [process, below of=pro1] {Do something};
\node (pro3) [process, right of=pro2, xshift=4cm] {Do something};
\node (dec1) [decision, above of=pro3, yshift=0.4cm] {Check condition?};
\node (out1) [io, above of = dec1, yshift=0.4cm] {Output something};
\node (stop) [startstop, above = 0.5 of out1] {Stop};
\node (fit1) [dashed, rounded corners, fill=none, fit=(in1) (pro2), draw] {};
\node (fit2) [dashed, rounded corners, fill=none, fit=(pro3) (out1), draw] {};
\node[rotate=90, anchor=south] at (fit1.west) {The first step};
\node[rotate=90, anchor=south] at (fit2.west) {The second step};

\draw [arrow] (start) -- (in1);
\draw [arrow] (in1) -- (pro1);
\draw [arrow] (pro1) -- (pro2);
\draw [arrow] (pro2) -- (pro3);
\draw [arrow] (pro3) -- (dec1);
\draw (dec1.east) node[above right, xshift=0.4cm] {False}; \node[above left] at (dec1.north) {True};
\draw [arrow] (dec1.east) -- +(1,0) |- (pro3);
\draw [arrow] (dec1) -- (out1);
\draw [arrow] (out1) -- (stop);
\end{tikzpicture}
\end{figure}

\end{document}

Best Answer

Node with fit=<node name> actually consider width of the text in node with shapes trapezium and diamond and not their shapes extremes. This means, that we need to consider <node name>.bottom left corner and <node name>.top right corner at trapezium and <node name>.west and <node name>.east at diamond shapes.

\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{chains,
                fit,
                positioning,
                shapes}

\begin{document}
    \begin{tikzpicture}[
   node distance = 8mm and 12mm,
     start chain = A going below,
     start chain = B going above,
     base/.style = {draw, align=center, 
                    inner sep=2mm, on chain=A, join=by arr},
startstop/.style = {base, rounded rectangle},
       io/.style = {base, text width=42mm, trapezium, trapezium stretches body,
                    trapezium left angle=75, trapezium right angle=105},
  process/.style = {base, text width=44mm, minimum height=1cm},
 decision/.style = {base, text width=40mm, diamond, aspect=2, inner xsep=-4mm},
      arr/.style = {-stealth}
                        ]
\node   [startstop] {Start};                        % A-1
\node   [io] {$V$: an input sample vector \\ 
              $\alpha$: a user-specified number};
\node   [process] {Do something};
\node   [process] {Do something};                   % A-4
    \node (f1) [draw, rounded corners, dashed, 
                fit=(A-2.bottom left corner) (A-2.top right corner) (A-4),
                label={[rotate=90, anchor=south]left:The first step}] {};
%  
    \begin{scope}[base/.append style={on chain=B}]  % B-1
\node   [process, right=of A-4] {Do something};
\node   [decision]      {Check condition?};
\node   [io]            {Output something};
\node   [startstop]     {Stop};                     % B-4
    \end{scope}
%
\draw[arr]  (A-4) -- (B-1);
\draw[arr] (B-2.east) node (false) [above right] {False} -- + (1,0) |- (B-1);
\node[above left] at (B-2.north) {True};
%
    \node (f2) [draw, rounded corners, dashed, 
                fit=(B-1) (B-3.bottom left corner) (B-3.top right corner) (false),
                label={[rotate=90,anchor=south]left:The second step}] {};
    \end{tikzpicture}
\end{document}

Note: node names are determined by chain name: A-i for nodes in the left branch of the flowchart and B-i for nodes in the right branch.

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

The source of the difficulty is that ellipses are constructed in a particular way in TikZ. They are paths that start from the x-axis and proceed counter-clockwise around their centre. The vast majority of the time, the exact parametrisation doesn't matter. You appear to have found the one situation where it does!

In the actual question, you only want to be able to mirror the ellipse, and so draw it starting from the negative x-axis (the title of the question suggests a more flexible approach). That's actually not too hard since we can exploit the symmetry of the ellipse. The key is to provide it with a negative x-radius, since then it will start from the negative x-axis (and proceed clockwise, but we could correct for that by negating the y-radius as well). To do this, we interrupt the call from the node shape to the drawing command and flip the sign of the x-radius. The simplest way to do this is to redefine the \pgfpathellipse macro to do the negation and then call the original macro. The following code does this.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations,shapes,decorations.markings}
\makeatletter
\let\origpgfpathellipse=\pgfpathellipse
\def\revpgfpathellipse#1#2#3{%
  #2%
  \pgf@xa=-\pgf@x
  \origpgfpathellipse{#1}{\pgfqpoint{\pgf@xa}{0pt}}{#3}}
\makeatother

\tikzset{
  reversed ellipse/.style={
    ellipse,
    reverse the ellipse%
  },
  reverse the ellipse/.code={
    \let\pgfpathellipse=\revpgfpathellipse
  }
}
\begin{document}
\begin{tikzpicture}
\node[ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,0) {hello world};

\node[reversed ellipse,
  draw,
  postaction={
    decorate,
    decoration={
      markings,
      mark=at position 1 with {
        \arrow[line width=5pt,blue]{>}
      }
    }
  }
] at (0,-2) {hello world};
\end{tikzpicture}

\end{document}

Here's the result:

rotated ellipse

(the arrow got clipped, but you can see where it lies)

[Tex/LaTex] UML Statediagram

You could make your state node into a 'multipart' node. For that, you need to load the shapes.multipart TikZ library. You should then be able to use all the placement options that you're used to.

Result:

enter image description here

Code:

\documentclass[border=1cm]{standalone}
\usepackage{tikz}
\usetikzlibrary{shapes.multipart}    
\begin{document}
  \begin{tikzpicture}
    \node[rectangle split, rectangle split parts=2, draw, rounded corners]{%
      \tikz\node[draw=red, rectangle, rounded corners]{titel};
      \nodepart{two}
      \begin{tabular}{c}
      content \\ more content
      \end{tabular}
    };
  \end{tikzpicture}
\end{document}

PS. You might alternatively make your state node into a matrix, but then it's quite hard to get the horizontal line that you want (see this discussion, for instance).

Best Answer

Related Solutions

[Tex/LaTex] Rotate a node but not its content: the case of the ellipse decoration

[Tex/LaTex] UML Statediagram

Related Question