calculationstikz-pgf
How can I put abs inside a coordinate calculation in TikZ? I have tried the following but it doesn't work (see lines 4 and 5 inside the MWE).
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{calc}
\newcommand{\asd}[1]{\node[circle,draw] at ($(1+#1,0)$) {B};} %this works
\newcommand{\zxc}[1]{\node[circle,draw] at ($abs(#1),0$) {B};} %this doesn't
\begin{document}
\begin{tikzpicture}
\node[circle,draw] at (1,0) {A};
\zxc{-2}
\end{tikzpicture}
\end{document}
I am definitely unfamiliar with both beamer and tikz (do not quite get what the \only are supposed to do) but perhaps this could go in the direction you want:
\documentclass{beamer}
\usepackage{tikz}
\usetikzlibrary{chains}
\newcounter{count}
% helper macro:
\long\def\GobToSemiColon #1;{}
\newcommand\myPicture{
\begin{tikzpicture}
\begin{scope}[start chain = going below]
\ifnum\value{count}<1 \expandafter\GobToSemiColon\fi
\ifnum\value{count}>3 \expandafter\GobToSemiColon\fi
\node[draw, rectangle, on chain] {display only when counter is between
1 and 3};
\ifnum\value{count}>-1 \expandafter\GobToSemiColon\fi
\node[draw, rectangle, on chain] {display only when counter is
negative};
\ifnum\value{count}<100 \expandafter\GobToSemiColon\fi
\ifnum\value{count}>200 \expandafter\GobToSemiColon\fi
\node[draw, rectangle, on chain] {display only if counter is between
100 and 200};
\ifnum\value{count}<3 \expandafter\GobToSemiColon\fi
\ifnum\value{count}>20 \expandafter\GobToSemiColon\fi
\node[draw, circle, on chain] {only when counter is in the range 3 to 20};
\end{scope}
\end{tikzpicture}
}
\begin{document}
\begin{frame}
\only{\setcounter{count}{-3}\myPicture}
\only{\setcounter{count}{105}\myPicture}
\only{\setcounter{count}{39}\myPicture}
\only{\setcounter{count}{2}\myPicture}
\only{\setcounter{count}{5}\myPicture}
\end{frame}
\end{document}
use
\begin{landscape}
\resizebox{!}{0.95\textheight}{\input{erd.tikz.tex}}
\end{landscape}
The image is too big. The reason why it is placed on the following page.
Best Answer
You will need to use
($({abs(#1)},0)$), firstly we of course need()inside the coordinate calculation. Secondly in{abs(#1)}, the{}'s are needed to ensure that the expression is passed on to evaluation and thus does not croak the parser that might be looking for()'s and|-etc