algorithmicalgorithms
I'm trying to write an algorithm in latex, but after I put my if statement it gives me back an error and says that there's a missing number. What does that mean? Where is my flaw? This is what I've written (mind you I'm trying to write a generalized algorithm that doesn't necessarily examine things, hence the general statement in if):
\For{j = length($y_i$)}{
\If{$\{x_j$ and $\neg x_j\}$ in $y_i$}{
\State \text{$a_i$ = F}
}
Can I do that?
The algorithmicx package provides a \Comment command which does what you need, and is customizable. In this example I've created a macro with two arguments, one for each column of the annotation. Then each line gets inserted with a \Comment command. I've also redefined the standard \Comment format macro (\algorithmiccomment) with the \algrenewcommand macro to remove the arrow that shows up by default.
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{algpseudocode}
\usepackage{algorithm}
\usepackage{array}
\newcolumntype{L}{>{$}l<{$}}
\newcommand\cpair[2]{%
\begin{tabular}{LL}#1 & #2\end{tabular}}
\algrenewcommand{\algorithmiccomment}[1]{\hfill#1}
\begin{document}
\begin{algorithm}
\caption{Insertion-Sort køretid}\label{AlgRun}
\begin{algorithmic}[1]
\Procedure{insertion-sort}{$A,n$} \Comment \cpair{c_1}{n=0}
\State $inversions = 0$ \Comment \cpair{c_1}{n=1}
\State \textit{L}[0..\textit{n} - 1] be a new array.
\For{q=0}{n-1}
\State L[q] = A[q]
\EndFor
\For{j=1}{n-1}
\State $key = L[j]$
\State $i = j - 1$
\While{$ i \geq 0$ \textbf{and} $L[i] > key$}
\State L[ i + 1] = L[ i ]
\State $j = i - 1$
\State $inversions = inversions + 1$
\EndWhile
$L[i + 1] = key$
\EndFor
\Return{inversions}
\EndProcedure
\end{algorithmic}
\end{algorithm}
\end{document}
Store the counter and restore it using TeX's \label-\ref system and the support of refcount:
\documentclass{article}
\usepackage{algorithm,algorithmic,refcount}
\begin{document}
\begin{algorithm}
\begin{algorithmic}[1]
\STATE First step
\STATE Second step
\STATE Third step
\STATE Fourth step \label{alg:last-step}
\end{algorithmic}
\end{algorithm}
\begin{algorithm}
\begin{algorithmic}[1]
\setcounterref{ALC@line}{alg:last-step}
\STATE Fifth step
\STATE Sixth step
\end{algorithmic}
\end{algorithm}
\end{document}
Note that algorithmicx provides \algsave and \algrestore, specifically for this purpose.
Best Answer
It seems you're mixing up the syntax of
algpseudocodewith that ofalgorithm2e.With the former package, the syntax is like as follows
The latter package has no
\Statecommand, so I guess you're usingalgpseudocode.Note the changes I made to your input to use math mode wherever it's needed.