MATLAB: Using three 60000 x 1 double matrices, how to make the 3D graph efficiently in the form of 2D

griddatalarge datameshmeshgridscatteredinterpolant

Hello, Simply, I need to make use 3 matrices which are 60000 x 1 size each. When I use the code below, I have a serious performance problem and I cannot complete the meshgrid because of the large matrices. How can I implement what I need to do? Thanks
        clc
        clear all
        a=rand(60000,1);
        b=rand(60000,1);
        c=rand(60000,1);
        [X,Y]=meshgrid(a,b);
        Z=griddata(a,b,c,X,Y,'cubic');
        mesh(X,Y,Z)

Best Answer

Right now, your meshgird command is attempting to create 2 60000x60000 matrices... which are going to require around 26 GB each. However, luckily, that's not actually what you want to do.
Is your real data actually completely scattered, as in this example? Or does it already lie on a grid, but is simply stored in vectors?
If it's truly scattered:
F = scatteredInterpolant(x,y,z);
[x,y] = meshgrid(linspace(min(a),max(a),100), linspace(min(b),max(b),100));
z = F(x,y);
mesh(x,y,z);
If it lies on a grid already, you can eliminate the triagulation and simply rearrange your data into the appropriate grids.
Related Question