MATLAB: Using fminbnd to find the max value.

fminbndfunctionmax point

How can I find the max value between 0.5 – 5 using fminbnd?

m=.09
b=2.7
Eq1=@(x)   b.*(x.^m)
% I try this but I get an error
Maxp=fminbnd(Eq1.*-1,0.5,5)

[Bestx, Maxp] = fminbnd(@(x) -Eq1(x), 0.5, 5)

Using linear inequalities

   A=[0 0 1 -1];
   b=0;
   lb=[0 0 0 0];
   ub=[5 5 inf 1];
   x=fmincon(fun,x0,A,b,[],[],lb,ub);

You have a discrete system. You can just search for its extremes directly.

x=-10:.0001:10
f = (2+(x-1.45).^2)./(3+3.5.*(.8.*x.^2-.6.*x+2))
[fmin, minidx] = min(f);
xmin = x(minidx);
[fmax, maxidx] = max(f);
xmax = x(maxidx);

If you want to use a continuous system then:

f = @(x) (2+(x-1.45).^2)./(3+3.5.*(.8.*x.^2-.6.*x+2));
[xmin, fmin] = fminbnd(f, [-10 10]);
[xmax, fmax] = fminbnd(@(x) -f(x), [10 10]);