MATLAB: Using a variable in fopen

fopenvariablevariables

I want to run a loop that will access files from multiple folders
I used dir to retrieve the names of the folders and I want to be able to feed the names into fopen.
ex:
folder = dir('W:\Examples')
#_of_folders = numel(folder)
for i=1:#_of_folders
fid = fopen('W:\Examples\folder([i])')
…
end
How can I enter that variable into fopen? Is there a better way of achieving this?
I did take a look at this thread, but I am still having trouble.
http://www.mathworks.com/matlabcentral/answers/114582-how-i-use-a-variable-name-to-do-a-fid-fopen
Thank you

Best Answer

 init = 'W:\Examples';
 folder = dir(init)
 for i  = 1:numel(folder)
  % do something with folder(i) to figure out if it's a file you want to open, or a folder you want to search, and if so:
 filename = [init '\' folder(i).name]; % or  filename = [init '\' folder(i).name '\' folder(i).name '.abc']; if you know that the folders contain files with the same name as the folder and a fixed extension...
 % do something with filename
 fid =  fopen(filename,'r');
 end
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