MATLAB: Subscripted assignment dimension mismatch.

MATLAB

 for i=1:i
      var(1,i) = find(m1==indexes(1,i));
       end

error is var(1,i) = find(m1==indexes(1,i));

Best Answer

The result of the find is likely a vector, and it appears you are trying to stuff this vector into a scalar spot. Do you need all of the find results, or maybe just one of them? If you need all of them, can you use a cell array for var? What is var being used for downstream in your code?

Related Solutions

MATLAB: Subscript assignment mismatch.

If you delete d(1,1) what is the expected result? You can't do it unless d is a cell array

For example:

d=[1 2 3;4 5 6]

If you delete the first element

d(1,1)=[];

What are you expecting as result? is it a matrix? what kind of matrix that rows are not the same size! You can define a cell array

d={1 2 3;4 5 6}
d(1,1)={[]}

MATLAB: Subscripted assignment dimension mismatch.

The error message means, that

all_nodes.estimated(i,:)

and

inv(transpose(A)*A)\transpose(A)*B

do not have matching dimensions. Simply enable the debugger:

dbstop if error

and start your code again. When Matlab stops at the error, check the sizes by typing in the command window:

size(inv(transpose(A)*A)\transpose(A)*B)
size(all_nodes.estimated(i,:))

Perhaps another problem: Does this what you expect:

row_neighbor_anchor = 1:M-1;
W = zeros(1, row_neighbor_anchor);

Now W is a multi-dimensional array with M-1 dimensions. Later on:

for j=row_neighbor_anchor
  W(j,:) = ...

it looks, like you expect that W is a matrix and you add more rows to it.

Best Answer

Related Solutions

MATLAB: Subscript assignment mismatch.

MATLAB: Subscripted assignment dimension mismatch.

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