MATLAB: Stumped again… Converting Python to Matlab

python

Here is the bit of Python code I am trying to convert to Matlab. code:
# thetas for each panel in global frame
theta=np.zeros((numPanels,1))
for i in range(numPanels):
    theta[i]=np.arctan2(yp[i+1]-yp[i],xp[i+1]-xp[i])
output:
-2.63356
-2.92712
-2.98475
-3.01668
-3.03837
-3.05471
-3.06785
-3.07891
-3.08853
-3.09713
-3.10498
-3.11228
-3.11917
-3.12577
-3.13217
-3.13846
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.14159
3.13846
3.13217
3.12577
3.11917
3.11228
3.10498
3.09713
3.08853
3.07891
3.06785
3.05471
3.03837
3.01668
2.98475
2.92712
2.63356
0.508031
0.21447
0.156842
0.124909
0.103226
0.0868853
0.0737421
0.0626828
0.053059
0.0444609
0.0366123
0.0293165
0.0224263
0.0158261
0.00942088
0.00312805
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
-0.00312805
-0.00942088
-0.0158261
-0.0224263
-0.0293165
-0.0366123
-0.0444609
-0.053059
-0.0626828
-0.0737421
-0.0868853
-0.103226
-0.124909
-0.156842
-0.21447
-0.508031
These are my Matlab arrays, where xpAdd = xp[i+1] and xp = xp[i]
xpAdd =
    0.0600
    0.0581
    0.0562
    0.0544
    0.0525
    0.0506
    0.0488
    0.0469
    0.0450
    0.0431
    0.0412
    0.0394
    0.0375
    0.0356
    0.0319
    0.0300
    0.0281
    0.0262
    0.0244
    0.0225
    0.0206
    0.0188
    0.0169
    0.0150
    0.0131
    0.0112
    0.0094
    0.0075
    0.0056
    0.0038
    0.0019
         0
   -0.0019
   -0.0038
   -0.0056
   -0.0075
   -0.0094
   -0.0112
   -0.0131
   -0.0150
   -0.0169
   -0.0188
   -0.0206
   -0.0225
   -0.0244
   -0.0262
   -0.0281
   -0.0300
   -0.0319
   -0.0338
   -0.0356
   -0.0375
   -0.0394
   -0.0412
   -0.0431
   -0.0450
   -0.0469
   -0.0488
   -0.0506
   -0.0525
   -0.0544
   -0.0562
   -0.0581
   -0.0600
   -0.0600
   -0.0581
   -0.0562
   -0.0544
   -0.0525
   -0.0506
   -0.0488
   -0.0469
   -0.0450
   -0.0431
   -0.0412
   -0.0394
   -0.0375
   -0.0356
   -0.0319
   -0.0300
   -0.0281
   -0.0262
   -0.0244
   -0.0225
   -0.0206
   -0.0188
   -0.0169
   -0.0150
   -0.0131
   -0.0112
   -0.0094
   -0.0075
   -0.0056
   -0.0038
   -0.0019
         0
    0.0019
    0.0038
    0.0056
    0.0075
    0.0094
    0.0112
    0.0131
    0.0150
    0.0169
    0.0188
    0.0206
    0.0225
    0.0244
    0.0262
    0.0281
    0.0300
    0.0319
    0.0338
    0.0356
    0.0375
    0.0394
    0.0412
    0.0431
    0.0450
    0.0469
    0.0488
    0.0506
    0.0525
    0.0544
    0.0562
    0.0581
    0.0600
xp' =
    0.0600
    0.0581
    0.0562
    0.0544
    0.0525
    0.0506
    0.0488
    0.0469
    0.0450
    0.0431
    0.0412
    0.0394
    0.0375
    0.0356
    0.0319
    0.0300
    0.0281
    0.0262
    0.0244
    0.0225
    0.0206
    0.0188
    0.0169
    0.0150
    0.0131
    0.0112
    0.0094
    0.0075
    0.0056
    0.0038
    0.0019
         0
   -0.0019
   -0.0038
   -0.0056
   -0.0075
   -0.0094
   -0.0112
   -0.0131
   -0.0150
   -0.0169
   -0.0188
   -0.0206
   -0.0225
   -0.0244
   -0.0262
   -0.0281
   -0.0300
   -0.0319
   -0.0338
   -0.0356
   -0.0375
   -0.0394
   -0.0412
   -0.0431
   -0.0450
   -0.0469
   -0.0488
   -0.0506
   -0.0525
   -0.0544
   -0.0562
   -0.0581
   -0.0600
Does anyone have an idea what this is doing theta[i]=np.arctan2(yp[i+1]-yp[i],xp[i+1]-xp[i]) ? I believe it's finding the angle and x1 and x2 points.

Best Answer

It is finding the angle from (xp(i),yp(i)) to (xp(i+1),yp(i+1))
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