MATLAB: Precision of datatype complex

complexdatatypeMATLABprecision

Hi,

can someone give me a answer of the precision of a complex value of matlab. is the wohle value double or each part (real,im) ?

kind regards Alex

Best Answer

The real and the imaginary parts are stored in a double. Therefore a complex double occupies 2*8 bytes.

Related Solutions

MATLAB: Matlab integer format for answer

Try a function, like int32(), fix(), ceil(), floor(), uint8(), int32(round()), etc.

a = (2+24)/(4*3) % Floating point.
aInteger = int32(a)
whos aInteger; % int32
aInteger = round(a)
whos aInteger; % Double


aInteger = floor(a)
whos aInteger; % Double
aInteger = ceil(a)
whos aInteger; % Double
aInteger = fix(a)
whos aInteger; % double
aInteger = uint16(a)
whos aInteger; % uint16

Note that with round(), ceil(), floor(), and fix() you will end up with a double but with no fractional part. If you want an actual integer, you have to cast to an integer data type with int32(), int16(), etc.

MATLAB: Datatypes

Your command

double e1,e2,e;

is equivalent to

double('e1')
e2
e

'e1' is a string, which is an array of character, and applying double to the array of character returns the numeric values of each of the characters: that happens to be 101 for 'e' and 49 for '2'. For more information on this, please see Command vs Function syntax

In MATLAB, one does not declare variables as being of a particular type: one just assigns values and the variable assumes the type of the values if the variable appears by itself (without any kind of indexing) in an assignment syntax.

Best Answer

Related Solutions

MATLAB: Matlab integer format for answer

MATLAB: Datatypes

Related Question