MATLAB: Phase response with conjugate poles

bodeplot

Hello! I have a doubt with Bode plot. The TF is:
100
-------
s^2 + 2
And the bode plot is
Phase should not start at 0° and goes down to -180°; instead of 360° and going up to -180°?

Best Answer

It behaves correctly when I plot it (in R2017a):
s = tf('s');
sys = 100/(s^2 + 2);
figure(1)
pzplot(sys)
figure(2)
bode(sys)
The problem of not sharing all the relevant parts of your code with us is that we have no idea what you did to get the result you posted.
Related Question