MATLAB: Partial Differentiation of a function partial differentiation syms x y f=x^2+2*y^2-22 P=diff(f,x) Here, I have calculated the (partial) differentiation of function "f" w.r.t 'x' Now, I want to know the value of 'P' at certain point (say x=1.5, y=2.0) Please help! Best Answer One of the possibilities:syms x yf=x^2+2*y^2-22P=diff(f,x)subs(P,{x,y},{1.5,2}) Related SolutionsMATLAB: How to find total derivative Hey Kanav,Check out "diff" in the Symbolic Math Toolbox. One thing to note is that for the form you want, you need to explicitly define y as a function of x.syms x y(x)diff(cos(x) - sin(y)*x,x)returns- sin(y(x)) - sin(x) - x*cos(y(x))*diff(y(x), x)-Adam MATLAB: Hello, I want to derive from a function such as (f=f0+R*f1+R^2*f2+R^3*f3) so that the answer is as follows: (f’=f0’+R*f1’+R^2*f2’+R^3*f3′) syms f(x) f0(x) f1(x) f2(x) f3(x) Rfun=diff(f,x)==diff(f0,x)+R*diff(f1,x)+R^2*diff(f2,x)+R^3*diff(f3,x) Related QuestionDerivative firstly x then yHow to find the mixed partial derivatives using MatlabHow to code a function of relative rates
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