MATLAB: Hello, I want to derive from a function such as (f=f0+Rf1+R^2f2+R^3f3) so that the answer is as follows: (f’=f0’+Rf1’+R^2f2’+R^3f3′)

diff()function

The values of the functions f are not given in x and we want to calculate the derivative parametric

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syms f(x) f0(x) f1(x) f2(x) f3(x) R
fun=diff(f,x)==diff(f0,x)+R*diff(f1,x)+R^2*diff(f2,x)+R^3*diff(f3,x)

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MATLAB: When I run the program inaccurate results appear What is the problem

The best approach to this is likely not the vpasolve function, since it takes forever.

I have no idea of these are the ‘accurate’ results you want (I have no idea what that means), however you will get them much more quickly:

syms t y1 y2 y3 y4  yn11 yn1 yr yr11 yr111   yr v y(v) x
format longe
h=0.1;
r=1.7686999343761197980595002942562;   %1694/911=1.859495060373216e+00
x=0;
y0=0;
y01=0.25;
y011=0;
fn=-y01+y0.*y01.*y011;
fnr=-yr11+yr.*yr11.*yr111;
fn1=-yn1+y1.*yn1.*yn11;
fn2=-y3+y2.*y3.*y4;
eq1 =-y2-(r - 2)/r*y0+ 2/(r*(r - 1))*yr+ (2*r - 4)/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 - 23*r + 6))/(120*r)*fn+ (h.^3.*(- r^2 + 2*r + 3))/(60*r)*fnr -(h.^3.*(- r^3 + 4*r^2 + 9*r - 26))/60*fn1+ (h.^3.*(- r^3 + 2*r + 1))/120*fn2;
eq1 = simplifyFraction(eq1);
eq1d = vpa(eq1, 5)
eq2= -h.*y3 -(r - 3)/r*y0+ 3/(r*(r - 1))*yr+ (r - 4)/(r - 1)*y1 -(h.^3.*(3*r^4 - 24*r^3 + 66*r^2 - 67*r + 12))/(240*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r - 4))/(40*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- 3*r^4 + 15*r^3 + 15*r^2 - 137*r + 116))/(120*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 + 3*r - 12))/(80*(r - 2))*fn2;
eq2 = simplifyFraction(eq2);
eq2d = vpa(eq2, 5)
eq3=-h.^2.*y4+2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1+ (h.^3.*(- r^4 + 8*r^3 - 22*r^2 + 18*r + 5))/(120*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r + 5))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- r^4 + 5*r^3 + 5*r^2 - 75*r + 77))/(60*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 + 42*r - 81))/(120*(r - 2))*fn2;
eq3 = simplifyFraction(eq3);
eq3d = vpa(eq3, 5)
eq4=-h.*yn1 -(r - 1)/r*y0+ 1/(r*(r - 1))*yr+ (r - 2)/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 - 21*r + 6))/(240*r)*fn+ (h.^3.*(- r^2 + 2*r + 3))/(120*r)*fnr -(h.^3.*(- r^3 + 4*r^2 + 9*r - 8))/120*fn1 -(h.^3.*(r^3 - 2*r + 1))/240*fn2;
eq4 = simplifyFraction(eq4);
eq4d = vpa(eq4, 5)
eq5=-h.^2.*yn11+ 2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 - 28*r + 10))/(120*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r - 10))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- r^4 + 5*r^3 + 5*r^2 - 35*r + 22))/(60*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 - 8*r + 4))/(120*(r - 2))*fn2;
eq5 = simplifyFraction(eq5);
eq5d = vpa(eq5, 5)
eq6=-h.*yr11+ (r - 1)/r*y0+ (2*r - 1)/(r*(r - 1))*yr -r/(r - 1)*y1+ (h.^3.*(2*r^4 - 13*r^3 + 28*r^2 - 22*r + 5))/240*fn+ (h.^3.*(4*r^3 - 15*r^2 + 10*r + 5))/(120*(r - 2))*fnr+ (h.^3.*r*(- 2*r^3 + 7*r^2 + 2*r - 3))/120*fn1+ (h.^3.*r*(2*r^4 - 5*r^3 + 2*r^2 + 2*r - 1))/(240*(r - 2))*fn2;
eq6 = simplifyFraction(eq6);
eq6d = vpa(eq6, 5)
eq7=-h.^2.*yr111+ 2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1+ (h.^3.*(4*r^4 - 22*r^3 + 38*r^2 - 22*r + 5))/(120*r)*fn -(h.^3.*(- 14*r^4 + 55*r^3 - 55*r^2 + 5*r + 5))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(4*r^4 - 15*r^3 + 5*r^2 + 5*r - 3))/(60*(r - 1))*fn1+ (h.^3.*(4*r^4 - 8*r^3 + 2*r^2 + 2*r - 1))/(120*(r - 2))*fn2;
eq7 = simplifyFraction(eq7);
eq7d = vpa(eq7, 5)
eq8=-h.*y01 -(r + 1)/r*y0 -1/(r*(r - 1))*yr+ r/(r - 1)*y1+ (h.^3.*(r^3 - 8*r^2 + 22*r - 5))/240*fn+ (h.^3.*(r^3 - 5*r^2 + 5*r + 5))/(120*(r^2 - 3*r + 2))*fnr+ (h.^3.*r*(- r^3 + 5*r^2 + 5*r - 3))/(120*(r - 1))*fn1 -(h.^3.*r*(- r^3 + 2*r^2 + 2*r - 1))/(240*(r - 2))*fn2;
eq8 = simplifyFraction(eq8);
eq8d = vpa(eq8, 5)
eq9 =-h.^2.*y011+ 2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 + 22*r - 5))/(120*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r + 5))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- r^4 + 5*r^3 + 5*r^2 + 5*r - 3))/(60*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 + 2*r - 1))/(120*(r - 2))*fn2;
eq9 = simplifyFraction(eq9);
eq9d = vpa(eq9, 5)
eqsfcn = matlabFunction([eq1,eq2,eq3,eq4,eq5,eq6,eq7,eq8,eq9], 'Vars',{[y1,y2,y3,y4,yn1,yn11,yr,yr11,yr111]})
eqsol = fsolve(eqsfcn, rand(1,9))
eqsolc = num2cell(eqsol);
[y1,y2,y3,y4,yn1,yn11,yr,yr11,yr111] = eqsolc{:}

I used the simplifyFraction function to do just that with your equations, then the fsolve function to do the actual calculations. These changes make it significantly more efficient.

The results I got are:

y1 =
     2.495835158216658e-02
y2 =
     4.966725033036157e-02
y3 =
     2.450145921764798e-01
y4 =
    -4.970810349993776e-02
yn1 =
     2.487509121241510e-01
yn11 =
    -2.496352514349295e-02
yr =
     4.398727143758653e-02
yr11 =
     2.460985502335340e-01
yr111 =
    -4.401564490668385e-02

You must be certain your equations are written as you want them to be in order to get ‘accurate’ values. We have no control over that.

Experiment to get the results you want.

MATLAB: How to write f”’ + f’f” = 0 in matlab

YOu can write first,second and third derivative like below:

df = diff(f,t) ;   %f'
d2f = diff(f,t,t) ; % f''
d3f = diff(f,t,t,t) ; % f'''

Check below option also:

syms f(t)  
df = diff(f,t) ;
d2f = diff(df,t) ;
d3f = diff(d2f,t) ;
ode = d3f+df*d2f == 0
dsolve(ode)

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MATLAB: When I run the program inaccurate results appear What is the problem

MATLAB: How to write f”’ + f’f” = 0 in matlab

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