MATLAB: Matrix dimension error. i can understand why it is showing but cannot get any solution

MATLABmatrix

i have A1 which 2×2 matrix and B1 which 2×1 matrix. i have a system

A1*Y=B1.

i wish to solve it by

Y = A1/B1;

but it shows

error matrix dimension must agree.

i can understand why it is showing like this, but how to solve this problem?

    A1 = [x1,(r11*X1+r12*Y1+r13*Z1+Tx);x2,(r11*X2+r12*Y2+r13*Z2+Tx)];
    B1 = [-x1*(r31*X1+r32*Y1+r33*Z1);-x2*(r31*X2+r32*Y2+r33*Z2)];
    Y = A1/B1;
    disp(Y);

please let me know

Best Answer

Are you sure you want A1/B1 and not A1\B1 ?

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xdata = horzcat(x1,x2,x3);
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fun=@(b,xdata) horzcat((b(1)+b(4))*x1./(1+b(1)*x1+b(2)*x2+b(3)*x3),(b(2)+b(5))*x2./(1+b(1)*x1+b(2)*x2+b(3)*x3),(b(3)+b(6))*x3./(1+b(1)*x1+b(2)*x2+b(3)*x3));
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Best wishes

Torsten.

MATLAB: How to rearrange the output variables for matlabFunction()

I can’t run the code you posted, since it generates significant errors about matrix size multiplication.

However, a simple example demonstrates how to order the arguments:

syms a b c d x1 x2 x3 x4 
e = a*x1+b*x2+c*x3+d*x4;
E = matlabFunction(e, 'Vars',{[x1 x2 x3 x4],c a b d})

producing:

E =
  function_handle with value:
    @(in1,c,a,b,d)a.*in1(:,1)+b.*in1(:,2)+c.*in1(:,3)+d.*in1(:,4)

So the arguments are ordered in the sequence requested, and the parameters are grouped together as ‘in1’ in a separate parameter vector, in the event you need to do that.

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