MATLAB: Matlab wont generate vector, [1E-15:10:1E-12]

arrayvectorvectors

It will generate vectors with much simpler inputs, but not this one.

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How many elements does the vector have that you desire to see? That 10 in there is not the number of steps to be taken, but the additive increment.

The first element will be 1e-15.

Ok, then the increment is 10, so we will have 1e-15 + 10. Oh. But that exceeds 1e-12. Darn. So MATLAB gives up at 1e-15. What is the problem, except for not knowing how the colon operator is defined to work? I'll guess that you really wanted to use either linspace or logspace?

Don't forget to use the right display format for that result too. With some display formats, 1e-15 may be displayed as zero.

help format

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OK. Provided that the zeros appear periodically just the way you have shown in your code, you could use

 indz = find(A==0);                  % find positions of zeros in A
 numr = indz(2)-indz(1)-1;           % compute the constant(!) row lengths
 A(A == 0) = [];
 B = reshape(A,numr,length(A)/numr)

Again, if there is not a constant number of non-zero elements in each interval (that includes also the last interval) you end up with different row lengths. In that case you cannot build a matrix that satisfies your requirements.

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