MATLAB: Input function must return ‘double’ or ‘single’ values. Found ‘sym’.

integral symbolicMATLAB

dear all
when i using integral command although i define z i get the following error 
clc
clear all
E2=10;
E1=20;
lE=E2/E1;
n=1;
h=2;
v1=30;
v2=40;
lv=v2/v1;
sym z
Eb=1+(((2*z+h)/2*h)^n)*(lE-1) 
vb=1+(((2*z+h)/2*h)^n)*(lv-1) 
fun=@(z) Eb/((1-(v1^2)*(vb^2))*h)
A11=integral(fun,-1/2,1/2)
and the error :
Undefined function or variable 'z'.
Error in first (line 13)
Eb=1+(((2*z+h)/2*h)^n)*(lE-1)
and also when i use syms z instead of sym z i get the following one :
fun =
  function_handle with value:
    @(z)Eb/((1-(v1^2)*(vb^2))*h)
Error using integralCalc/finalInputChecks (line 511)
Input function must return 'double' or 'single' values. Found 'sym'.
Error in integralCalc/iterateScalarValued (line 315)
                finalInputChecks(x,fx);
Error in integralCalc/vadapt (line 132)
            [q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75)
        [q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in first (line 18)
A11=integral(fun,-1/2,1/2)
i really appreciated if someone could help me with this

Best Answer

Correct syntax is to use 'syms', not 'sym'. Also you should use matlabFunction to convert symbolic equation to numeric
clc
clear all
E2=10;
E1=20;
lE=E2/E1;
n=1;
h=2;
v1=30;
v2=40;
lv=v2/v1;
syms z
Eb=1+(((2*z+h)/2*h)^n)*(lE-1) 
vb=1+(((2*z+h)/2*h)^n)*(lv-1) 
fun= matlabFunction(Eb/((1-(v1^2)*(vb^2))*h))
A11=integral(fun,-1/2,1/2)
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