MATLAB: Problem with function handle

Question

alpha
alpha =
  function_handle with value:
    @(z)(z-b)/a
>> qa
qa =
  function_handle with value:
    @(z)sqrt((1./alpha.^2)-p.^2)
>> t = integral(qa,0,3)
Undefined operator '.^' for input arguments of type 'function_handle'.
Error in @(z)sqrt((1./alpha.^2)-p.^2)
Error in integralCalc/iterateScalarValued (line 314)
                fx = FUN(t);
Error in integralCalc/vadapt (line 132)
            [q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75)
        [q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);

Answer 1

EDITED

syms z
a=1; % an example datas
b=2;
p=3;
alpha=(z-b)/a;
qa=sqrt((1./(alpha.^2)-p.^2));
t = integral(matlabFunction(qa),0,3)