MATLAB: I would like to create an array of cosnx with n=0,1,2,3…N…

arraycos arrayMATLAB

I would like to create an array of cos*n*x with n=0,1,2,3…N.

My code looks like this but it does not run.

L=51

N=(L-1)/2;

i=0;

for i=0:N

A=(:,i)=cos(i*pi);

end

Best Answer

Why do you need a loop?

L = 51;
N = (L-1)/2;
A = cos((0:N)*pi)
A = 1×26
     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1     1    -1

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MATLAB: How to concatenate -x:x for x=0,1,2,3,..n without a loop

Constructing it as a vector is possible in theory.

The value range -N to +N is in the (N+1)'th group and is a vector of length (2*N+1). The total length of the vector to the end of the -N:+N group can be found to be (N+1)^2 . Therefore for any given position, M, floor(sqrt(M-1)-1) tells you how many complete N have been gone through, and M minus that gives you the relative position in progress:

Nb = floor(sqrt(M-1)-1);
value_at_M = M - (Nb+1).^2 - 1 + -(Nb+1);

For any given final N, Nf, you can run that vectorized:

M = 1 : (Nf+1).^2;
Nb = floor(sqrt(M-1)-1);
value_at_M = M - (Nb+1).^2 - 1 + -(Nb+1);

"2. How can I call the takesquare with additional parameters? So the idea is adding different values to each row"

You only have one row.

MATLAB: Median of n*n

median(A(:))

When you are working in MATLAB, get used to the idea that you can reshape a matrix to perform some operation.

Best Answer

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MATLAB: How to concatenate -x:x for x=0,1,2,3,..n without a loop

MATLAB: Median of n*n

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