MATLAB: Median of n*n MATLABmedian I have an n*n and would like to find the medianof the entire set n*n not of the individual rows or coloumns as can be found by: median(A) or median(A,2) etc.. Best Answer median(A(:))When you are working in MATLAB, get used to the idea that you can reshape a matrix to perform some operation. Related SolutionsMATLAB: How to calculate the area which located between curve and x-axis Try this:X = [1427.18976 1427.21024 1427.23072 1427.2512 1427.27168 1427.29216 1427.31264 1427.33312 1427.3536 1427.37408 1427.39456 1427.41504 1427.43552 1427.456];Y = [2098.083 2231.598 1888.275 1945.497 3280.65 6656.64 7667.55 7286.07 7514.94 7324.23 7095.33 6980.91 7534.02 7400.52];Z = trapz(X, Y) MATLAB: Calculation with if else statement You need to create a logical index (a "map") first of where A is less than its median. Then use that logical index to make the assignmentA = rand(10, 60, 1200); % Create sample data.median_A = median(A(:))max_A = max(A(:))min_A = min(A(:))% Find where A is less than it's median.logicalIndexes = A <= median_A; % A 3-D logical array.% First initialize everything:anomaly = ((median_A - A)./(max_A - median_A)*100);% Make up second set of numbers.A2 = ((median_A - A)./(median_A - min_A)*100);% Then replace only those indexes where A(i,j,k) < median_Aanomaly(logicalIndexes) = A2(logicalIndexes);Also, look up the mad() and isoutier() functions. Related QuestionInterX issues. Showing intersection when there is none.How to create a random 10×10 matrix with values between -10 and 10
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