Is there a way that I can get the first occurrence of consecutively repeating values, even if the same value occurs at few different places in the matrix?
Say I have a matrix
X=[2 2 2 2 -1 -1 -1 6 6 6 6 6 5 5 5 2 2 2 2 7 7 6 6]
I want the result to be
ans=[2 -1 6 5 2 7 6].
I've checked a similar question How to remove repeating elements from an array but using unique and keeping the same order as original matrix gives
ans=[2 -1 6 5 7].
I know I can use a loop like below. But I was wondering if there's a function for this.
for i=1:(length(X)-1) if (X(i+1,6)-X(i,6))~=0 ans(i,1)=X(i+1,6); else ans(i,1)=NaN; endend
A function to do this will be great.
Best Answer