MATLAB: The difference in an array

finding the difference in values

sum(abs(diff([5 3 6 1 5 1 6 7 3])))

A=[1 2 3 2 1 4 5 6 7 5 2 0 4 5 6 10]
[peaks,idx]=findpeaks(A)

If you haven't a signal processing toolbox

A=[5 2 3 2 1 4 5 6 7 5 2 0 4 5 6 10]
d=sign([0 diff(A)]);
idx=strfind(d,[1,-1])

It looks like you want the sum of the absolute value of the differential of those numbers? You get your first answer like this:

abs_diff = abs(diff([0 1 1 0 1 1 0]))

You would then sum these values. If all you want is the final answer, this is how to do it:

answer = sum(abs(diff([0 1 1 0 1 1 0])))