MATLAB: How to determine the area limited by f(t)= exp(-0.01.t.^2).cos(2.*t) and g(t) =0.4 for t Ԑ [1, 3.5].

curves area

Because of other operations done before both f(t) and g(t) is used with handles(@) in my code. Tried other methods that are on this forum but cant get them to work due to the two curves doesn't intersect.

f = @ (t) exp(-0.01.*t.^2).*cos(2.*t)

Best Answer

integral( @(t) abs(f(t) - 0.4), 1, 3.5)

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MATLAB: How to integrate integral(integral(cos(t),-10,t) ,t1,t2)

The intermediate integration is numerical in nature so the operation needs to be vectorized. Unfortunately the integral function does not handle vectors for integral limits. Try the following

F = @(t) cos(t);
A = @(t) arrayfun(@(s)-integral(F,-10,s),s);
Z = @(t1,t2) -integral(A,t1,t2);

MATLAB: Help! plotting i(t) vs t.

You cannot list a subscripted variable on the "function" line of a definition.

function iamps = i(t)

You also need to change the {} to ()

iamps = (3+5*sin(2*t-pi)+t*exp(-t))*(u(t)-u(t-2*pi));  %{} became ()

If you are planning to pass a vector of t in, then you need to convert the * into .* in order to vectorize-- In MATLAB, * is algebraic matrix multiplication, not element-by-element multiplication.

   iamps = (3+5*sin(2*t-pi)+t.*exp(-t)).*(u(t)-u(t-2*pi));  %vectorize as well

Best Answer

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MATLAB: How to integrate integral(i​ntegral(co​s(t),-10,t​) ,t1,t2)

MATLAB: Help! plotting i(t) vs t.

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MATLAB: How to integrate integral(integral(cos(t),-10,t) ,t1,t2)