MATLAB: How to convolute two discrete impulse functions

convolutionsignal processing

Im having a few issues trying to figure out the syntax to convolute two discrete impulse functions. any help on the syntax would be great. here are the two signals

x[n]= -delta[n+1] + 0.5delta[n] + 2delta[n-1] h[n]= 2delta[n] + delta[n-1]

Best Answer

 x[n]= -delta[n+1] + 0.5delta[n] + 2delta[n-1]
 h[n]= 2delta[n] + delta[n-1]

"I don't know how to write the two signals in matlab"

So basically your signals are

 x = [-1, 0.5, 2];
 h = [1, 2];

You can convolve the two signals by using

 y = conv(x, h);

Use the different options (under the heading 'shape' in the input arguments part) given in the help section and see which one is suitable for your use.

Related Solutions

MATLAB: Convolute two functions(two signals)

function x = myconv(t) 
x = abs(t) < pi/2;
end
w=conv(x,x);
plot(w)

like that what're you think?

MATLAB: Attempted to access delta(-2); index must be a positive integer or logical. Error in ==> ANC at 20 h(n)=delta(n-3)-2.7083delta(n-4)+4.1861delta(n-5)-3.0451delta(n-6)+0.73071delta(n-7);

When n is 1, n-3 is -2

You loop over n is going to have trouble unless you start at n = 8

What you initialize h(1) through h(7) to is a good question.

By the way, consider conv() with fliplr([0, 0, 1, -2.7083, +4.1861, -3.0451, +0.73071])

Best Answer

Related Solutions

MATLAB: Convolute two functions(two signals)

MATLAB: Attempted to access delta(-2); index must be a positive integer or logical. Error in ==> ANC at 20 h(n)=delta​(n-3)-2.70​83*delta(n​-4)+4.1861​*delta(n-5​)-3.0451*d​elta(n-6)+​0.73071*de​lta(n-7);

Related Question

MATLAB: Attempted to access delta(-2); index must be a positive integer or logical. Error in ==> ANC at 20 h(n)=delta(n-3)-2.7083delta(n-4)+4.1861delta(n-5)-3.0451delta(n-6)+0.73071delta(n-7);