MATLAB: How to convert 1×1 sym into numeric value in the workspace

1x1 symconvert into numeric valuesystemsystem of equations

I need to solve this system of equations and I need to obtain the numerical value of all coefficient also in the workspace.
In order to solve this system I used:
sol = solve([eqn1, eqn2, eqn3, eqn4, eqn5, eqn6, eqn7, eqn8, eqn9, eqn10], [A1 B1 A2 B2 A3 B3 A4 B4 A5 B5 A6 B6 A7 B7 A8 B8 A9 B9 A10 B10]);
The results in the workspace are:
How I can obtain numeric values of the coefficients? I need to put them also in the workspace.
Which is the meaning of 1×1 sym? what is the problem?
Here there is the same code if you need to try on yourself:
syms A1 B1 A2 B2 A3 B3 A4 B4 A5 B5 A6 B6 A7 B7 A8 B8 A9 B9 A10 B10;
    eqn1 = A1-B1==0; 
    eqn2 = A1*exp(2*3)+B1*exp(-2*3)==A2*exp(2*3)+B2*exp(-2*3);
    eqn3 = A1*exp(2*3)-B1*exp(-2*3)==(1/2)*(A2*exp(2*3)+B2*exp(-2*3))+(180/2);
    eqn4 = A2*exp(2*2)+B2*exp(-2*2)==A3*exp(2*2)+B3*exp(-2*2);
    eqn5 = A2*exp(2*2)-B2*exp(-2*2)==(A3*exp(2*2)-B3*exp(-2*2))+(180/2);
    eqn6 = A3*exp(2*3)+B3*exp(-2*3)==(4/(3^2*4^2*12*4*4i*10))*(A4*exp(4*3)-B4*exp(-4*3));
    eqn7 = A3*exp(2*3)-B3*exp(-2*3)==(2/(3^2*4^2*12*4*4i*10))*(A4*exp(4*3)+B4*exp(-4*3));
    eqn8 = A4*exp(4*4)+B4*exp(-4*4)==(12/2)*(A5*exp(5*4)+B5*exp(-5*4));
    eqn9 = A4*exp(4*4)-B4*exp(-4*4)==(12/(2*2))*(A5*exp(5*4)-B5*exp(-5*4));
    eqn10 = A5*exp(5*5)+B5*exp(-5*5)==0;
sol = solve([eqn1, eqn2, eqn3, eqn4, eqn5, eqn6, eqn7, eqn8, eqn9, eqn10], [A1 B1 A2 B2 A3 B3 A4 B4 A5 B5 A6 B6 A7 B7 A8 B8 A9 B9 A10 B10]);

Best Answer

A ‘1 x 1 sym’ is a single scalar symbolic expression, while: 
Q = sym('Q', [2 3])
creates a ‘2 x 3’ symbolic expression.
If you want the numeric value of ‘A1’ (or any of the others that do not contain symbolic variables — I did not check all of them to be certain that they do not — refer to them with respect to the ‘sol’ structure: 
A1d = double(sol.A1)
producing: 
A1d =
   0.446183616140603
.
Related Question