List={[5,2] [27,19] [13,8] [17,14] [3,13] [21,20] [6,16] [4,30] [1,13] [20,2] [14,27]; [5,2] [21,7] [29,6] [17,36] [35,12] [8,20] [35,8] [11,10] [35,23] [22,25] [9,32]};B={[21 20]};A=ismember(List{1,:}, B) % it will only check the row of the cell List.
result=[0 0 0 0 0 1 0 0 0 0 0]
is it possible?
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