MATLAB: Problem with an if statement

if statement

Dear all,
I have A =[
1 2 0 2 11 0;
2 3 0 30 11 -2;
3 4 0 28 12 -6;
4 5 0 25 1 -9;
5 6 0 22 2 -6;
6 7 0 22 3 -12;
7 8 0 19 4 -13;
8 9 0 17 5 -17;
9 10 0 14 6 -18;
10 11 0 12 7 -22;
11 12 0 9 8 -25;
12 13 0 6 9 -26;
13 14 0 4 10 -30;
14 15 0 1 11 -1;
15 16 0 29 11 -3;
16 17 0 27 12 0;
17 18 0 31 1 -3;
18 19 0 28 2 0;
19 20 0 28 3 -6;
20 21 0 25 4 -7;
21 22 0 23 5 -11;
22 23 0 20 6 -12;
23 24 0 18 7 -16;
24 25 0 15 8 -19;
25 26 0 12 9 -20;
26 27 0 10 10 -24;
27 28 0 7 11 -25;
28 29 0 5 12 -29;
29 30 0 2 1 -1;
30 31 0 30 1 -4;
31 32 0 27 2 -1;
32 33 0 27 3 -7;
33 34 0 24 4 -8;
34 35 0 22 5 -12;
35 36 0 19 6 -13;
36 37 0 17 7 -17;
37 38 0 14 8 -20;
38 39 0 11 9 -21;
39 39 0 9 10 -2]
I want to apply the following if statement: if the fourth column is 1 or 2 AND the fifth column contains identical successive numbers AND the element in the laste column in not zero then replace every other corresponding element in the third column with the corresponding element (in absolute value) from the last column
The if statement should select the following elements
B=[
14 15 0 1 11 -1;
15 16 0 29 11 -3;
29 30 0 2 1 -1;
30 31 0 30 1 -4;]
and then the action is to obtain
B=[
14 15 1 1 11 -1;
15 16 0 29 11 -3;
29 30 1 2 1 -1;
30 31 0 30 1 -4;]
So the new A should be
Anew =[
1 2 0 2 11 0;
2 3 0 30 11 -2;
3 4 0 28 12 -6;
4 5 0 25 1 -9;
5 6 0 22 2 -6;
6 7 0 22 3 -12;
7 8 0 19 4 -13;
8 9 0 17 5 -17;
9 10 0 14 6 -18;
10 11 0 12 7 -22;
11 12 0 9 8 -25;
12 13 0 6 9 -26;
13 14 0 4 10 -30;
14 15 1 1 11 -1;
15 16 0 29 11 -3;
16 17 0 27 12 0;
17 18 0 31 1 -3;
18 19 0 28 2 0;
19 20 0 28 3 -6;
20 21 0 25 4 -7;
21 22 0 23 5 -11;
22 23 0 20 6 -12;
23 24 0 18 7 -16;
24 25 0 15 8 -19;
25 26 0 12 9 -20;
26 27 0 10 10 -24;
27 28 0 7 11 -25;
28 29 0 5 12 -29;
29 30 1 2 1 -1;
30 31 0 30 1 -4;
31 32 0 27 2 -1;
32 33 0 27 3 -7;
33 34 0 24 4 -8;
34 35 0 22 5 -12;
35 36 0 19 6 -13;
36 37 0 17 7 -17;
37 38 0 14 8 -20;
38 39 0 11 9 -21;
39 39 0 9 10 -2]
Is there a clever coding for this?

Best Answer

Okay, think I know what you mean... this should do it.
c5 = [A(2:end,5); NaN];
idx = ((A(:,4)==1)|(A(:,4)==2))&(A(:,5)==c5)&(A(:,6)~=0);
B = A(idx,:);
A(idx,3) = abs(A(idx,6));
Tested with your example and gives the correct value for A.