MATLAB: How i extract the components of a vector/matrix output

regression linear

For example i have a function like a=polyfit(x,y,1) and the result is

a= 0.300 1.00

How can i extract a(1)=0.300 and a(2)=1.00?Thank you

Best Answer

Yes, that is the syntax. a(1) and a(2)

a=polyfit(x,y,1);
first_element = a(1);
second_element = a(2);

Read about indexing here: https://www.mathworks.com/company/newsletters/articles/matrix-indexing-in-matlab.html

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MATLAB: How to print a table

This should be close to what you want. However, I have used the logical not, and, and or functions which appear to be diffferent that your definitions of functionNot, functionAnd, and functionOr. You can replace these with calls to your functions.


%start with a clear workspace and command window
clearvars; clc;
%Create two array (x,y)
x=[1 1 1 0 0 0 2 2 2];
y=[1 0 2 1 0 2 1 0 2];
%print the header
fprintf('    x    y   tNot(x) tAnd(x,y)  tOr(x,y)\n');
% print the results
for r=1:9
    fprintf('%5d%5d%10d%10d%10d\n', x(r), y(r), not(x(r)), and(x(r), y(r)), or(x(r), y(r)));
end

Result:

    x    y   tNot(x) tAnd(x,y)  tOr(x,y)
    1    1         0         1         1
    1    0         0         0         1
    1    2         0         1         1
    0    1         1         0         1
    0    0         1         0         0
    0    2         1         0         1
    2    1         0         1         1
    2    0         0         0         1
    2    2         0         1         1

MATLAB: Vector/matrix Initialization

The first two blocks don't make much sense. Assuming that the one of those if conditions is true then vector k will get defined with the same three value (in different orders). The vector k is then used to remove some values from v, but the order is irrelevant. k is not used again (it gets reassigned in the third block of code). Therefore the first two blocks are simply equivalent to:

 v = 1:length(s);
 v([i1,i,i0]) = [];

Best Answer

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MATLAB: How to print a table

MATLAB: Vector/matrix Initialization

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