MATLAB: How can I solve difference equation with initial condition.

difference equationfilterMATLAB

Consider a difference equation with its initial conditions.

5y(n)+y(n-1)-3y(n-2) = (1/5^n)u(n), n>=0 y(n-1) = 2, y(n-2) = 0

How can I determine y(n) in matlab?

See the FILTER command

Hi Javier,

as far as I understood your question you want to create a new vector with

 for i=1:lenght(A)
   if A(i)>0
     C(i) = B(i)
   end
 end

This could be done in with the for loop above, but the fastest way should be via logical indexing.

 C = zeros(size(A));
 flag_a = A >0   % is logical 1 where elements are bigger zero 
 C(flag_a) = B(flag_a);

best, Stephan

Use the hold function.

figure
scatter3(x(w1), y(w1), z(w1), 'y', 'filled')
hold on
scatter3( ...)
scatter3( ...)
scatter3( ...)
scatter3( ...)
hold off