With respect to
syms t1 t2 t3
R1 = [
cos(t2)*cos(t3) - sin(t2)*sin(t3), - cos(t2)*sin(t3) - cos(t3)*sin(t2), 0, 10*cos(t2);
(7344817515977723*cos(t2)*sin(t3))/9223372036854775808 + (7344817515977723*cos(t3)*sin(t2))/9223372036854775808, (7344817515977723*cos(t2)*cos(t3))/9223372036854775808 - (7344817515977723*sin(t2)*sin(t3))/9223372036854775808, 9007196398844849/9007199254740992, (36724087579888615*sin(t2))/4611686018427387904 + 45035981994224245/4503599627370496;
- (9007196398844849*cos(t2)*sin(t3))/9007199254740992 - (9007196398844849*cos(t3)*sin(t2))/9007199254740992, (9007196398844849*sin(t2)*sin(t3))/9007199254740992 - (9007196398844849*cos(t2)*cos(t3))/9007199254740992, 7344817515977723/9223372036854775808, 36724087579888615/4611686018427387904 - (45035981994224245*sin(t2))/4503599627370496;
0, 0, 0, 1];
P = [
(433*cos(t1))/500, -cos(t1)/2, sin(t1), 0;
-(433*sin(t1))/500, sin(t1)/2, cos(t1), 0;
-1/2, 433/500, 0, 0;
0, 0, 0, 1];
there is no possible solution for R1 == P.
Compare R1(3,3) = 7344817515977723/9223372036854775808 to P(3,3) = 0. These are constants but do not equal each other, so it is not possible to find t1, t2, t3 that will make the matrices equal.
Best Answer