MATLAB: Find unknown from the equation with limited given value

equationfsolveunknown

100=(1/Me)*((2+(g-1)*Me^2)/(g+1))^((g+1)/(2*(g-1))) g = 1.24

Best Answer

syms Me
g = 1.24
Me=vpasolve((1/Me)*((2+(g-1)*Me^2)/(g+1))^((g+1)/(2*(g-1)))==100,Me)

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MATLAB: Need help solving two unknown variable equations

Try this:

syms a b 
eqn_1 = 20*log10((1 + ((20/a).^(2*b))).^(1/2))== 0.316;
eqn_2 = 20*log10((1 + ((150/a).^(2*b))).^(1/2))==33;
[a,b] = vpasolve([eqn_1,eqn_2],[a,b])

ANSWER

    a =
    33.350407439877975992438632838773
    b =
    2.526670930138947892001693474408

YOUR MISTAKES

1) syms f n should be syms a b

2) To view solution sol.a and sol.b you would get your answer because you received them in the form of struct so. to view struct with fields you just simply add dot in between.

MATLAB: Can one use fsolve with symbolic value equations

It’s a bit difficult to follow what you’re doing, but if you want to use symbolic expressions and you don’t mind slow code, use the solve function.

the fsolve function will find the values where the argument function equates to zero, so if you want to do the same with your symbolic gradient, my answer to Finding the null gradient directly applies to your problem.

Best Answer

Related Solutions

MATLAB: Need help solving two unknown variable equations

MATLAB: Can one use fsolve with symbolic value equations

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