MATLAB: Find groups of 1’s in array

groupImage Processing Toolboxone

Sorry but ı have asked question wrong.

thanks all for great attention.

For example the data 11101111001110001111110100000000011111111 is like that and there only two groups of 1 could be because number of 0 maybe to few then we should accept them as a 1 how can we do that we have to find 1's group as a 2 there.

 Examples: 1111111111100111111111111111011111111111111111= Result:1
           1111111111100000000000000000111111111111111111= Result:2
          11111111111000000000001111111111110000000001111111111100000000111111111 =Result :4
          111111011111111010111111111101111111010011111111101001111111= Result :1
          111010101111101000000011100011111 =RESULT :3  LIKE THAT

Best Answer

 Nsplit = 5; % number of consecutive zeros that split a group
 Z = find(diff(x) == 1) - find(diff(x) == -1);
 Ngroups = sum(Z > Nsplit) + 1;

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MATLAB: Counting number of repeated elements

You can use regionprops() to get the length, then do something on each set of indexes where the length exceeds 360. If you have the Image Processing Toolbox, here's a start

% Find zeros, convert to binary, then label each region:
[labeledRegions, numRegions] = bwlabel(doubleVector == 0); 
% Measure lengths of each region, and get indexes of each region.
props = regionprops(labeledRegions, 'Area', 'PixelIdxList');
% Loop over all regions, looking for regions that are 360 elements or longer.
for k = 1 : numRegions
    % See if this stretch of zeros is 360 or longer.
    if props(k).Area >= 360
        % This stretch of zeros is 360 or longer.
        theseIndexes = props(k).PixelIdxList;
        % Now do something with these indexes.
    end
end

MATLAB: Count 1’s in binary

If you have the Image Processing Toolbox, it's just two real lines of code, a call to regionprops and a line to extract the lengths from what regionprops returns.

% Create sample binary data.
binaryArray = [0 0 1 1 1 1 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1]
% Measure lengths of stretches of 1's.
measurements = regionprops(logical(binaryArray), 'Area');
% Convert from structure to simple array of lengths.
allLengths = [measurements.Area]
% If you want 0's in between for some reason:
out = zeros(1, 2*length(allLengths)+1);
out(2:2:end) = allLengths

5000 numbers is no problem. This code can handle millions of them.

Best Answer

Related Solutions

MATLAB: Counting number of repeated elements

MATLAB: Count 1’s in binary

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